bug#65491: [PATCH] Improve performance allocating vectors

["Mattias Engdegård" <mattias.engdegard@gmail.com>]

16 sep. 2023 kl. 18.17 skrev Eli Zaretskii <eliz@gnu.org>:

>> The latter one completely broke the 32-bit build --with-wide-int, most
>> probably because the last argument to XUNTAG is frequently a pointer
>> to a 64-bit type, where uintptr_t is only 32-bit wide.
> 
> No, that's not it: the reason is that the _first_ argument is a 64-bit
> data type, and then casting XLP(a) to uintptr_t causes the warning,
> because uintptr_t is a 32-bit type.

Let's see if I understand this correctly, as I can't try that configuration myself.

In your configuration, Lisp_Object is a 64-bit integer (or a struct containing one).
LISP_WORD_TAG(type) is also a 64-bit integer with tag bits at the top (USE_LSB_TAG=0).
The old XUNTAG was:

#define XUNTAG(a, type, ctype) ((ctype *) \
				((char *) XLP (a) - LISP_WORD_TAG (type)))

so that we get a subtraction of a pointer and a very large 64-bit number, which results in just the pointer.

The new XUNTAG is:

#define XUNTAG(a, type, ctype) ((ctype *) \
				((uintptr_t) XLP (a) - LISP_WORD_TAG (type)))

so you get a warning from what, conversion of a 64-bit number to (ctype *)?
Does changing the definition to

#define XUNTAG(a, type, ctype) \
  ((ctype *) ((uintptr_t) XLP (a) - (uintptr_t)LISP_WORD_TAG (type)))

help? (That is, cast the LISP_WORD_TAG return value to uintptr_t.)