* bug#16106: 24.3.50; doc of `replace-match'
@ 2013-12-10 23:56 Drew Adams
2014-02-08 2:54 ` Lars Ingebrigtsen
0 siblings, 1 reply; 4+ messages in thread
From: Drew Adams @ 2013-12-10 23:56 UTC (permalink / raw)
To: 16106
State (in doc string and Elisp manual) that N in \N is not just "a
digit" but a digit from 1 through 9. Make clear that in "Nth
subexpression", N is one-based, not zero-based.
In GNU Emacs 24.3.50.2 (i686-pc-mingw32)
of 2013-11-28 on LEG570
Bzr revision: 115271 rgm@gnu.org-20131128203155-qjc1xsp19z2k64b2
Windowing system distributor `Microsoft Corp.', version 6.1.7601
Configured using:
`configure --enable-checking 'CFLAGS=-O0 -g3' CPPFLAGS=-DGLYPH_DEBUG=1'
^ permalink raw reply [flat|nested] 4+ messages in thread
* bug#16106: 24.3.50; doc of `replace-match'
2013-12-10 23:56 bug#16106: 24.3.50; doc of `replace-match' Drew Adams
@ 2014-02-08 2:54 ` Lars Ingebrigtsen
2014-02-08 3:33 ` Drew Adams
0 siblings, 1 reply; 4+ messages in thread
From: Lars Ingebrigtsen @ 2014-02-08 2:54 UTC (permalink / raw)
To: Drew Adams; +Cc: 16106
Drew Adams <drew.adams@oracle.com> writes:
> State (in doc string and Elisp manual) that N in \N is not just "a
> digit" but a digit from 1 through 9. Make clear that in "Nth
> subexpression", N is one-based, not zero-based.
I don't think that makes any sense. The wording is:
`\N' means substitute what matched the Nth `\(...\)'.
If Nth parens didn't match, substitute nothing.
I can't see anybody interpreting Nth as having "zeroth" as a valid
meaning.
--
(domestic pets only, the antidote for overdose, milk.)
bloggy blog http://lars.ingebrigtsen.no/
^ permalink raw reply [flat|nested] 4+ messages in thread
* bug#16106: 24.3.50; doc of `replace-match'
2014-02-08 2:54 ` Lars Ingebrigtsen
@ 2014-02-08 3:33 ` Drew Adams
2014-02-10 6:56 ` Drew Adams
0 siblings, 1 reply; 4+ messages in thread
From: Drew Adams @ 2014-02-08 3:33 UTC (permalink / raw)
To: Lars Ingebrigtsen; +Cc: 16106
> > State (in doc string and Elisp manual) that N in \N is not just "a
> > digit" but a digit from 1 through 9. Make clear that in "Nth
> > subexpression", N is one-based, not zero-based.
>
> I don't think that makes any sense. The wording is:
>
> `\N' means substitute what matched the Nth `\(...\)'.
> If Nth parens didn't match, substitute nothing.
>
> I can't see anybody interpreting Nth as having "zeroth" as a valid
> meaning.
Most things in Emacs and Lisp in general are zero-based.
It is not obvious that this is one-based. And Oth and zeroth
make as much sense as 1th and oneth. If counting is zero-based
then the 0th element is exactly that: the entry that is indexed
by the number zero.
^ permalink raw reply [flat|nested] 4+ messages in thread
* bug#16106: 24.3.50; doc of `replace-match'
2014-02-08 3:33 ` Drew Adams
@ 2014-02-10 6:56 ` Drew Adams
0 siblings, 0 replies; 4+ messages in thread
From: Drew Adams @ 2014-02-10 6:56 UTC (permalink / raw)
To: Lars Ingebrigtsen; +Cc: 16106
> Most things in Emacs and Lisp in general are zero-based.
> It is not obvious that this is one-based. And Oth and zeroth
> make as much sense as 1th and oneth. If counting is zero-based
> then the 0th element is exactly that: the entry that is indexed
> by the number zero.
Let me put it differently: Is there a good reason NOT to say that
"N is a digit from 1 through 9"?
^ permalink raw reply [flat|nested] 4+ messages in thread
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2013-12-10 23:56 bug#16106: 24.3.50; doc of `replace-match' Drew Adams
2014-02-08 2:54 ` Lars Ingebrigtsen
2014-02-08 3:33 ` Drew Adams
2014-02-10 6:56 ` Drew Adams
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