Re: [odt] equation labels

[Jambunathan K <kjambunathan@gmail.com>]

Myles

(I have read the followup post to this set of questions)

Myles English <mylesenglish@gmail.com> writes:
>>> On Mon, 31 Oct 2011 03:41:18 +0530, Jambunathan K said:
>
>   > Myles English <mylesenglish@gmail.com> writes:
>   >> I have found that Equations become labelled as Figures in the
>   >> version I am using:
>   >> 
>   >> emacs 23.3.1 org-mode from git commit 71f1c1be (Oct 26) The test
>   >> equations in latex-mathml.org in this message:
>   >> 
>   >> http://lists.gnu.org/archive/html/emacs-orgmode/2011-09/msg00198.html
>   >> 
>   >> are labelled as "Equation" in the odt files but when I export it
>   >> fresh I get "Figure".
>
>   > This was a regression. I pushed a fix few moments ago. Could you
>   > please pull again?
>
> Thanks for the push, there are three things I notice now:
>
> 1) my document won't open and causes libreoffice to crash! I get:
>    "terminate called after throwing an instance of
>      what():  vector::_M_default_append" on the command line

1. You are using custom styles for your latex fragment
2. latex-to-mathml converter - as it stands today - assumes the latex
   fragment is completed in and of itself and doesn't honor the style
   settings.

Putting 1 and 2 together, I am assuming that the XML created by the ODT
emitter contains garbage which is causing LibreOffice to be confused. In
my observation, ill-formed XML triggers "file is corrupt and should I
repair the file?" from LibreOffice. A crash seems strange to me.

1. http://article.gmane.org/gmane.emacs.orgmode/48714
   - Above link has my note on -ncf option to mathtoweb

2. http://orgmode.org/worg/org-faq.html
   - Above link has a note on how to debug corrupt odt files.
     (Hint: search for corrupt)

> 2) the first equation in latex-mathml.org is not numbered, I would
>    expect this if it was using a begin{equation*} environment but not a
>    begin{equation}.

Currently the odt exporter doesn't peek in to the latex fragment and
infer what manner of equation it is. This is something that I could take
up ...

,----
| (defvar org-latex-regexps
|   '(("begin" "^[ \t]*\\(\\\\begin{\\([a-zA-Z0-9\\*]+\\)[^\000]+?\\\\end{\\2}\\)" 1 t)
|     ;; ("$" "\\([ 	(]\\|^\\)\\(\\(\\([$]\\)\\([^ 	\r\n,.$].*?\\(\n.*?\\)\\{0,5\\}[^ 	\r\n,.$]\\)\\4\\)\\)\\([ 	.,?;:'\")]\\|$\\)" 2 nil)
|     ;; \000 in the following regex is needed for org-inside-LaTeX-fragment-p
|     ("$1" "\\([^$]\\|^\\)\\(\\$[^ 	\r\n,;.$]\\$\\)\\([- 	.,?;:'\")\000]\\|$\\)" 2 nil)
|     ("$" "\\([^$]\\|^\\)\\(\\(\\$\\([^ 	\r\n,;.$][^$\n\r]*?\\(\n[^$\n\r]*?\\)\\{0,2\\}[^ 	\r\n,.$]\\)\\$\\)\\)\\([- 	.,?;:'\")\000]\\|$\\)" 2 nil)
|     ("\\(" "\\\\([^\000]*?\\\\)" 0 nil)
|     ("\\[" "\\\\\\[[^\000]*?\\\\\\]" 0 nil)
|     ("$$" "\\$\\$[^\000]*?\\$\\$" 0 nil))
|   "Regular expressions for matching embedded LaTeX.")
`----


> 3) the second equation looks a bit like this:
>
>    x=root(b)               (1)
>    Radicals
>
>    but I would have expected something like:
>
>    x=root(b)
>    Equation 1.: Radicals
>
> Is there a new variable that I need to set to get (e.g.) "Equation
> 1."?

Being a non-latex user, I am not familiar with what the usual practice
is. If the latter option is how captioned equations are normally typeset
I can take it up. Can you confirm that the expectations above are *not*
your own but that of *any* user?

> Just to be explicit, the test file latex-mathml.org I am referring to
> contains:
>
> #+TITLE:     latex-mathml.org
> #+AUTHOR:    Jambunathan K
> #+EMAIL:     address@hidden
> #+DATE:      2011-09-09 Fri
> #+DESCRIPTION:
> #+KEYWORDS:
> #+LANGUAGE:  en
> #+OPTIONS:   H:3 num:t toc:t \n:nil @:t ::t |:t ^:t -:t f:t *:t <:t
> #+OPTIONS:   TeX:t LaTeX:t skip:nil d:nil todo:t pri:nil tags:not-in-toc
>
> #+EXPORT_SELECT_TAGS: export
> #+EXPORT_EXCLUDE_TAGS: noexport
> #+LINK_UP:   
> #+LINK_HOME: 
> #+XSLT:
>
> * LaTeX Fragments
>
> ** LaTeX Fragment1
> #   See org-format-latex-options
>
>     There is a equation down below.
>
>    \begin{equation}
>      e = \frac{1}{2}mv^2
>    \end{equation}
>
> ** LaTeX Fragment2
>
> #+CAPTION: Radicals
> #+LABEL: Equation:1
>    \begin{equation}
>    x=\sqrt{b}
>    \end{equation}
>
>    If $a^2=b$ and \( b=2 \), then the solution must be either $$
>    a=+\sqrt{2} $$ or \[ a=-\sqrt{2} \].
>
>
> Myles
>
>

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