From: Taylan Kammer <taylan.kammer@gmail.com>
To: Alexander Asteroth <alex@soeven.de>, guile-user@gnu.org
Subject: Re: letrec semantics
Date: Mon, 28 Nov 2022 15:07:39 +0100 [thread overview]
Message-ID: <8f5d8b22-f073-272f-004b-d18a14f7f166@gmail.com> (raw)
In-Reply-To: <87sfi379eb.fsf@soeven.de>
On 28.11.2022 09:33, Alexander Asteroth wrote:
>
>> scheme@(guile-user)> (letrec ((b a)(a 7)) b)
>> $1 = 7
>
> should be equivalent (of course in a new scope) to:
>
>> scheme@(guile-user)> (define b #nil)
>> scheme@(guile-user)> (define a #nil)
>> scheme@(guile-user)> (set! b a)
>> scheme@(guile-user)> (set! a 7)
>> scheme@(guile-user)> b
>> $2 = #nil
>
Hi Alex,
The only reason the first example returns 7 is because Guile *happens* to
bind a to 7 before it binds b to the value of a. The code could have as
well returned another value (IIRC Guile uses #<unspecified>) had Guile
decided to evaluate the arms of the letrec in a different order.
As per the part of the standard you quoted:
> the 〈init〉s are evaluated [...] (in some unspecified order)
That's what the "unspecified order" in the parentheses is referring to.
On the other hand, in your second code example, there's a strict order
in which the various expressions will be evaluated. In the moment you
type in (set! b a), the value of a has not yet been changed to 7.
If you want to use letrec but with a specific order of evaluation of the
arms, then you can use the letrec* variant:
> (letrec* ((a 7) (b a)) b)
> $1 = 7
This will definitely work, without relying on chance or an implementation
detail of Guile.
--
Taylan
next prev parent reply other threads:[~2022-11-28 14:07 UTC|newest]
Thread overview: 6+ messages / expand[flat|nested] mbox.gz Atom feed top
2022-11-28 8:33 letrec semantics Alexander Asteroth
2022-11-28 9:25 ` Jean Abou Samra
2022-11-30 17:23 ` Alexander Asteroth
2022-11-28 14:07 ` Taylan Kammer [this message]
2022-11-30 17:24 ` Alexander Asteroth
2022-12-01 9:30 ` Linus Björnstam
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