* apply
@ 2005-08-03 8:38 Aurelien Chanudet
2005-08-03 12:17 ` apply Mikael Djurfeldt
0 siblings, 1 reply; 2+ messages in thread
From: Aurelien Chanudet @ 2005-08-03 8:38 UTC (permalink / raw)
Hi all,
Consider the following code :
guile> (define x '( (1 1) (2 2) (3 3) ))
guile> (apply (lambda (a b c) (map list a b c) x)
((1 2 3) (1 2 3))
I can't figure out a concise an elegant way to achieve the same result
using a lambda form that will work whatever the length of x. Any
suggestion ?
Thanks,
Aurelien
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^ permalink raw reply [flat|nested] 2+ messages in thread
* Re: apply
2005-08-03 8:38 apply Aurelien Chanudet
@ 2005-08-03 12:17 ` Mikael Djurfeldt
0 siblings, 0 replies; 2+ messages in thread
From: Mikael Djurfeldt @ 2005-08-03 12:17 UTC (permalink / raw)
Cc: guile-user, Mikael Djurfeldt
On 8/3/05, Aurelien Chanudet <aurelien.chanudet@gmail.com> wrote:
> Hi all,
>
> Consider the following code :
>
> guile> (define x '( (1 1) (2 2) (3 3) ))
> guile> (apply (lambda (a b c) (map list a b c) x)
> ((1 2 3) (1 2 3))
>
> I can't figure out a concise an elegant way to achieve the same result
> using a lambda form that will work whatever the length of x. Any
> suggestion ?
Well, using a lambda form in the same way as above, it would be:
(apply (lambda args (apply map list args)) x)
but it's simpler to do
(apply map list x)
M
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