Re: Problem with cond macro.

[Joshua Judson Rosen <rozzin@geekspace.com>]

On Tue, Apr 16, 2002 at 12:45:40PM +0300, Panagiotis Vossos wrote:
> guile> (use-modules (ice-9 syncase))
> guile> (version)
> "1.5.6"
> guile> (define-syntax foo
> 	 (syntax-rules (=>)
> 	   ((_ a => b) b)
> 	   ((_ a b c) (+ a b c))))
> 
> (foo 10 => 20)
> (let ((=> 10))
>   (foo 10 => 20))
> guile> 20
> guile> 20
> 
> What am I doing wrong ?

Try using:
        (use-syntax (ice-9 syncase))
... rather than:
        (use-modules (ice-9 syncase))

Doing so gets me proper results for not only your example from above, but
also for the canonical example from r5rs.

It looks like this is because (use-syntax ...) imports the specified
module and then does:

       (set-module-transformer! (current-module) (car (last-pair spec)))

... where spec is, in this case, (ice-9 syncase), so it sets syncase
(which is defined in the file, psyntax.ss, as sc-expand) as the syntax
transformer for the current module, and this procedure, sc-expand,
does some necessary transformations that aren't done by guile's
default (null?) transformer.

Someone else would have to explain why guile's default macro-expanding
behaviour is what it is.

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