Re: case-lambda* question

["Germán A. Arias" <german@xelalug.org>]

Running this.

  (define f (case-lambda*
              ((x #:optional y) 1)
	     ((x #:key y)      2)
	     ((x y #:key z)    3)))

  (f 1 2)
  (f #:y 2)
  (f 1 2 #:z 3)

I get.

Backtrace:
In ice-9/boot-9.scm:
 157: 7 [catch #t #<catch-closure 8f15df0> ...]
In unknown file:
   ?: 6 [apply-smob/1 #<catch-closure 8f15df0>]
In ice-9/boot-9.scm:
  63: 5 [call-with-prompt prompt0 ...]
In ice-9/eval.scm:
 414: 4 [eval # #]
In ice-9/boot-9.scm:
2131: 3 [save-module-excursion #<procedure 8ed31c0 at
ice-9/boot-9.scm:3660:3 ()>]
3667: 2 [#<procedure 8ed31c0 at ice-9/boot-9.scm:3660:3 ()>]
In unknown file:
   ?: 1 [load-compiled/vm
"/home/german/.cache/guile/ccache/2.0-LE-4-2.0/home/german/Escritorio/test.scm.go"]
In /home/german/Escritorio/./test.scm:
   3: 0 [f 1 #<undefined> 2 #:z 3]

/home/german/Escritorio/./test.scm:3:10: In procedure f:
/home/german/Escritorio/./test.scm:3:10: In procedure #<procedure f (x
#:optional y) | (x #:key y) | (x y #:key z)>: Odd length of keyword
argument list

But there is one interest line

3: 0 [f 1 #<undefined> 2 #:z 3]

What mean this? That is taking the second argument as a keyword?