yes i'm using GNU Guile 3.0.7, https://www.gnu.org/software/guile/docs/master/guile.html/Syntax-Transformer-Helpers.html

i have tested a lot , even define-once again and i choose to use to assignment operators and portable code because the non-portable function do not bring more, finally it was not a bad idea to ask for a new function because we can do it with the actual toolbox...
Damien

On Thu, Sep 23, 2021 at 10:48 PM Taylan Kammer <taylan.kammer@gmail.com> wrote:
Responding to myself:

On 23.09.2021 22:27, Taylan Kammer wrote:

> I can't seem to find syntax-local-binding in Guile 2.2 or 3.0.  Did you
> have to import some special module, or are you using another version?

Worked when I imported (system syntax internal).

> Either way, I suspect that the following will not work with your macro:
>
>   (let ()
>     (let ()
>       (<$ x 1))
>     (display x)
>     (newline))

Indeed it doesn't work, though for a different reason:

  While compiling expression:
  Syntax error:
  unknown file:43:8: body should end with an expression in form (let () (<$ x 1))

That's because indeed the inner let expands into:

  (let ()
    (define x 1))

And there has to be at least one expression after the define.  So I tried:

  (let ()
    (let ()
      (<$ x 1)
      (newline))
    (display x)
    (newline))

And as I expected, it says 'x' is unbound:

  ;;; <stdin>:44:45: warning: possibly unbound variable `x'
  <$ : global scope : x

  ice-9/boot-9.scm:1685:16: In procedure raise-exception:
  Unbound variable: x

The only way it will work is if you never use nested scopes, but that will
lead to very strange Scheme code, and there will probably be many cases
where you accidentally use a nested scope without immediately noticing it.

Note also that definitions aren't allowed everywhere.  Consider this:

  (let ()
    (if 'whatever
        (<$ x 1)
        (<$ x 2))
    (display x)
    (newline))

It leads to:

  While compiling expression:
  Syntax error:
  unknown file:49:17: definition in expression context, where definitions are not allowed, in form (define x 1)

Because the arms of 'if' aren't allowed to be definitions.

--
Taylan