From: Roger Mason <rmason@mun.ca>
To: Org-Mode <emacs-orgmode@gnu.org>
Subject: Output result of source block to a file
Date: Wed, 05 Jun 2019 08:11:50 -0230 [thread overview]
Message-ID: <y658sug48lt.fsf@mun.ca> (raw)
Hello,
I want to output the result of the evaluation of a (python) source block
to a (graphics) file and have a link to the file inserted in the buffer.
Here is the code:
#+begin_src python :results value file :file scaleplot02.pdf :exports results :var data=test
import matplotlib.pyplot as plt
import csv
scale = []
lescale = []
cdscale = []
energy = []
leenergy = []
cdenergy = []
for row in data:
scale.append(float(row[0]))
energy.append(float(row[1]))
if int(row[2]) != 0:
lescale.append(float(row[0]))
leenergy.append(float(row[1]))
if int(row[3]) != 0:
cdscale.append(float(row[0]))
cdenergy.append(float(row[1]))
plt.plot(scale,energy, 'r+')
plt.plot(lescale,leenergy, 'go')
plt.plot(cdscale,cdenergy, 'bo')
plt.xlabel('scale')
plt.ylabel('energy (Ha)')
plt.title('Energy vs scale')
plt.legend()
plt.savefig(file)
print ("[[./%s]]" % file)
#+end_src
This is the error:
NameError: name 'file' is not defined
Obviously the syntax on the begin_src line is wrong, but what should it
be instead?
Thanks,
Roger
next reply other threads:[~2019-06-05 10:42 UTC|newest]
Thread overview: 12+ messages / expand[flat|nested] mbox.gz Atom feed top
2019-06-05 10:41 Roger Mason [this message]
2019-06-05 13:17 ` Output result of source block to a file stardiviner
2019-06-06 11:36 ` Roger Mason
2019-06-07 11:05 ` stardiviner
2019-06-06 18:04 ` Roger Mason
2019-06-06 21:12 ` John Kitchin
2019-06-07 10:00 ` Roger Mason
2019-06-07 15:01 ` John Kitchin
2019-06-08 10:51 ` Roger Mason
2019-06-08 20:40 ` John Kitchin
2019-06-05 13:33 ` Ken Mankoff
2019-06-06 11:48 ` Roger Mason
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