bug#66117: 30.0.50; `find-buffer-visiting' is slow when opening large number of buffers

["Gerd Möllmann" <gerd.moellmann@gmail.com>]

Ihor Radchenko <yantar92@posteo.net> writes:

> Gerd Möllmann <gerd.moellmann@gmail.com> writes:
>
>>> Both versions are actually clear for me. What was not clear for me is
>>> how the docstring explains my `let' example.
>>
>> Sorry, I've lost track what the let example is. 
>
> (defvar-local eval-tests/buffer-local-var 'default-value)
>

Thanks. 

> (with-temp-buffer
>     (setq-local eval-tests/buffer-local-var 'local-value)
>     (let ((eval-tests/buffer-local-var 'let-value))
>       ;; Let in a buffer with local binding does not change the
>       ;; default value for variable.
>       (should (eq 'default-value (default-value
>     'eval-tests/buffer-local-var)))))

I assume this is clear. Temp buffer has local value, the let changes the
local (current) value, default-value determines the value as if the
local values weren't there, and so on.

>
> (with-temp-buffer
>     ;; (setq-local eval-tests/buffer-local-var 'local-value)
>     (let ((eval-tests/buffer-local-var 'let-value))
>       ;; Let in a buffer with local binding does not change the
>       ;; default value for variable.
>       (should (eq 'let-value (default-value 'eval-tests/buffer-local-var)))))

Here, temp has no local value, so the current value is the global one.
Let changes the global (current) value, and default-value picks that up.

In both cases, I don't know if that's mentioned explicitly in some doc
string. It's the normal behavior of let with special variables (dynamic
variables). The current value that is set changes depending on
circumstances.