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Eric Abrahamsen wrote:

> I'm reading in files with dates in this format: "2011-11-25". I need to
> write them out as "2011/11/25". Instead of just manhandling the strings
> (I'll likely need this date information in other places) I wanted to
> parse the strings into proper date objects, then format them back into
> strings. `date-to-time' doesn't work because (parse-time-string
> "2011-11-15") gives me:
> 
> (nil nil nil 15 11 2011 nil nil nil)
> 
> Which is not acceptable to `encode-time', because it requires integers,
> not nil. I can't believe this is quite this complicated: do I really
> have to replace all the nils with 0 myself?
> 
> Any pointers gratefully accepted,
> 
> Eric

(format-time-string "%Y/%m/%d"
  (apply 'encode-time 0 0 0
    (nthcdr 3 (parse-time-string "2011-11-15"))))

==> "2011/11/15"