regexp-quote for replacements

regexp-quote for replacements

[Roland Winkler]

I want to construct replacement patterns automatically.
Does the following piece of code insert the value of bar in the
replacement, no matter what the string bar is?
The point is that I want the optional arg LITERAL of replace-match
to be nil.

(let* ((foo "foo")
       ;; this string should appear in the replacement
       (bar "bar.\\")
       ;; the following is like regexp-quote for replacements?
       (baz (replace-regexp-in-string "\\\\" "\\\\" bar nil t)))
  (string-match "\\(foo\\)" foo)
  (replace-match (concat "\\1 " baz " \\1") nil nil foo))


Thanks a lot,

Roland

Re: regexp-quote for replacements

[Stefan Monnier]

> I want to construct replacement patterns automatically.
> Does the following piece of code insert the value of bar in the
> replacement, no matter what the string bar is?
> The point is that I want the optional arg LITERAL of replace-match
> to be nil.

>        ;; the following is like regexp-quote for replacements?
>        (baz (replace-regexp-in-string "\\\\" "\\\\" bar nil t)))

Yes, this will do a "quote" w.r.t the `literal' argument of
replace-match.  But it won't protect from case-fiddling.  For that I think
the only solution is the `fixedcase' argument (i.e. global to the
whole replacement text).


        Stefan