replace-regexp-in-string bug?

replace-regexp-in-string bug?

[Lennart Borgman]

I want to create a regexp out of an unknown string with spaces. I am not 
sure about the number of spaces in the actual string to match so I want 
to do a replacement like this:

    (replace-regexp-in-string "\s-+" "\s-+" "some space" nil t)

However this returns "some space" instead of "some\s-+space" which I 
expected. Is this a bug or am I misunderstanding the arguments in some way?

Re: replace-regexp-in-string bug?

[Lennart Borgman]

Lennart Borgman wrote:

> I want to create a regexp out of an unknown string with spaces. I am 
> not sure about the number of spaces in the actual string to match so I 
> want to do a replacement like this:
>
>    (replace-regexp-in-string "\s-+" "\s-+" "some space" nil t)
>
> However this returns "some space" instead of "some\s-+space" which I 
> expected. Is this a bug or am I misunderstanding the arguments in some 
> way?

No, it was not a bug. I have to count my \. This works as expected using

   (replace-regexp-in-string "\\s-+" "\\s-+" "some space" nil t)

Sorry for the noise.

Re: replace-regexp-in-string bug?

[Andreas Schwab]

Lennart Borgman <lennart.borgman.073@student.lu.se> writes:

>    (replace-regexp-in-string "\s-+" "\s-+" "some space" nil t)

"\s-+" is the same as "s-+".  You need to use the proper read syntax for
strings, see "Syntax for Strings" in the Emacs Lisp manual.

Andreas.

-- 
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