Re: Characters saved mismatch?

[Angelo Graziosi <angelo.graziosi@alice.it>]

Il 07/05/2017 10:56, Yuri Khan ha scritto:
> On Sun, May 7, 2017 at 6:27 AM, Angelo Graziosi
> <angelo.graziosi@alice.it> wrote:
> 
>>    Wrote ‘c:/msys64/tmp/foo.text’ (8 characters)
>>
>> but
>>
>>    ls -l foo.text
>>    -rw-r--r-- 1 bingo bongo 10  7 mag 01.07 foo.text
>>
>> 10 bytes!
> 
> You are comparing a character count against a byte count. Well *of
> course* they are going to be different. The assumption “one character
> is encoded by one byte” has been false for quite a while now.
> 

Someone should explain the meaning of "Wrote ‘c:/msys64/tmp/foo.text’ (8 
characters)".

If it refers to the number of characters, my example contains 6 
characters: f-o-o-b-a-r and not 8.

As I wrote, in Windows Emacs uses DOS style, more precisely 'utf-8-dos'. 
That should mean 1 byte/ch and CR+LF for end line (RET). This mean that

foo RET
bar RET

should contain (3+2) * 2 = 10 bytes as, 'ls' shows..

Then, where does "Wrote ‘c:/msys64/tmp/foo.text’ (8 characters)" came 
from, on Windows?