Re: How to see the value of each char in a string?

[dkcombs@panix.com (David Combs)]

In article <uisyixb0z.fsf@ID-87814.user.dfncis.de>,
Oliver Scholz  <alkibiades@gmx.de> wrote:
>dkcombs@panix.com (David Combs) writes:
>[...]
>> , or, if fill-column happens to be 20:
>>
>>  (146 157 157 061 
>>  ("f" "o" "o" "2" 
>>
>> 063 146 157 157)
>> "3" "f" "o" "o")
>>
>> Like, maybe running through the string twice, each
>> time saving the result, and while generating each one,
>> inserting three newlines every so often,
>[...]
>
>Well, I think it is not possible (or at least very messy) to do this
>using the graphical representation of lists. What you wrote above
>would be the list
>
>(146 157 157 061 ("f" "o" "o" "2" 063 146 157 157) "3" "f" "o" "o")
>
>I must admit that I am not entirely sure that I understand what you
>want, despite your eplanation of your problem with `ls'. Maybe
>something like this?
>
>(require 'cl)
>
>(defun dc-display-ascii (string)
>  (interactive "sString: ")
>  (let ((standard-output (current-buffer)))
>    (pp (mapcar* 'cons
>		 (mapcar 'string string)
>		 (mapcar 'identity string)))))
>

Yes, thanks, does the trick.


>If you only want a convenient way to browse the ascii value of the
>chars in a string or buffer, you might want to have a look at the
>package ascii.el <URL: http://www.cpqd.com.br/~vinicius/emacs/ascii.el.gz>.

Now, *that* is one neat little tool!

How does one find out that such tools exist?

Thanks!

David