* replacement in string
@ 2008-06-03 6:58 alruccaba
0 siblings, 0 replies; 3+ messages in thread
From: alruccaba @ 2008-06-03 6:58 UTC (permalink / raw)
To: help-gnu-emacs
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Hallo everyone,
have an idea why this is it not working?:
replace-regexp-in-string "/" "\\" "a / b")
I just want to replace every "/" through an "\".
Debugger entered--Lisp error: (error "Invalid use of `\\' in replacement text")
replace-match("\\" nil nil "/" nil)
replace-regexp-in-string("/" "\\" "a / b")
eval((replace-regexp-in-string "/" "\\" "a / b"))
eval-expression((replace-regexp-in-string "/" "\\" "a / b") nil)
Greetings
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* Re: Re: replacement in string
@ 2008-06-03 11:53 alruccaba
2008-06-03 12:13 ` Peter Dyballa
0 siblings, 1 reply; 3+ messages in thread
From: alruccaba @ 2008-06-03 11:53 UTC (permalink / raw)
To: Ralf Angeli, help-gnu-emacs
Yes, I already quoted the letter, please see below. Your quotation works but it produces an "a \ b" and not "a b" what I intended to. I am struggeling with the commands (shell-command "command "c:/Dokumente und Einstellungen/.."") I hope this works anyway in this case. Very Thanks.
----- original Nachricht --------
Betreff: Re: replacement in string
Gesendet: Di 03 Jun 2008 09:41:00 CEST
Von: "Ralf Angeli"<dev.null@caeruleus.net>
> * alruccaba@justmail.de (2008-06-03) writes:
>
> > have an idea why this is it not working?:
> > replace-regexp-in-string "/" "\" "a / b")
> > I just want to replace every "/" through an "".
> > Debugger entered--Lisp error: (error "Invalid use of `\' in replacement
> text")
>
> You have to quote the backslash:
> (replace-regexp-in-string "/" "\\" "a / b")
>
> --
> Ralf
>
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* Re: replacement in string
2008-06-03 11:53 alruccaba
@ 2008-06-03 12:13 ` Peter Dyballa
0 siblings, 0 replies; 3+ messages in thread
From: Peter Dyballa @ 2008-06-03 12:13 UTC (permalink / raw)
To: alruccaba; +Cc: help-gnu-emacs, Ralf Angeli
Am 03.06.2008 um 13:53 schrieb alruccaba:
> Your quotation works but it produces an "a \ b" and not "a b" what
> I intended to.
Then use this:
(replace-regexp-in-string "/" "" "a / b")
The slash is replaced by nothing.
--
Mit friedvollen Grüßen
Pete
Who the fsck is "General Failure," and why is he reading my disk?
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2008-06-03 6:58 replacement in string alruccaba
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2008-06-03 11:53 alruccaba
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