Get the content of a list?

Get the content of a list?

[Herbert Euler]

Hello everyone,

I'm wanting to create a customized function to
wrap the standard 'call-process-region'. 'Call-
process-region' requires several arguments for
the program it called:

    (call-process-region START END PROGRAM &optional DELETE BUFFER DISPLAY 
&rest ARGS)

That is, several strings may be given as ARGS.
For example, the arguments can be

    "1" "2" "3"

But I don't know how to construct this series
of arguments. I can create a list

    ("1" "2" "3")

easily, but don't know how to convert it into
the former one. Any suggestions?

Thanks in advance.

Regards,
Guanpeng Xu

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Re: Get the content of a list?

[Pascal Bourguignon]

"Herbert Euler" <herberteuler@hotmail.com> writes:

> Hello everyone,
>
> I'm wanting to create a customized function to
> wrap the standard 'call-process-region'. 'Call-
> process-region' requires several arguments for
> the program it called:
>
>     (call-process-region START END PROGRAM &optional DELETE BUFFER
> DISPLAY &rest ARGS)
>
> That is, several strings may be given as ARGS.
> For example, the arguments can be
>
>     "1" "2" "3"
>
> But I don't know how to construct this series
> of arguments. I can create a list
>
>     ("1" "2" "3")
>
> easily, but don't know how to convert it into
> the former one. Any suggestions?

You can use apply to pass a list as the rest arguments:

(setf args '("1" "2" "3'))
(apply (function call-process-region)
        start end program delete buffer display args)


You can also put some or all previous arguments in the list too:

(setf args (list start end program delete buffer display "1" "2" "3'))
(apply (function call-process-region) args)


-- 
__Pascal Bourguignon__                     http://www.informatimago.com/

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