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From: Christian Johansson
Newsgroups: gmane.emacs.devel
Subject: Re: New package emacs-parser-generator
Date: Sun, 28 Nov 2021 14:45:40 +0100
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Cc: Eli Zaretskii , emacs-devel@gnu.org
To: Stefan Monnier
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Well the GLR(k) algorithm might find a nondeterminstic route route in the gr=
ammar that a LR(k) do not find, if I want to know if a code is syntatically c=
orrect I would test it against the same type of parser the language uses, th=
at is a deterministic parser
>=20
An intuitive structure - Tree-sitter=E2=80=99s output is a concrete syntax t=
ree; each node in the tree corresponds directly to a terminal or non-termina=
l symbol in the grammar. So in order to produce an easy-to-analyze tree, the=
re should be a direct correspondence between the symbols in your grammar and=
the recognizable constructs in the language. This might seem obvious, but i=
t is very different from the way that context-free grammars are often writte=
n in contexts like language specifications or Yacc/Bison parsers.
> https://tree-sitter.github.io/tree-sitter/creating-parsers#the-grammar-dsl=
This is a big issue because each version of a language grammar would need to=
be converted into tred-sitter form
But anyways I don't see the issue with pluralism in the parser generator spa=
ce, why would one exclude the other?
Regards
Christian
> 28 nov. 2021 kl. 14:24 skrev Stefan Monnier :
>=20
> =EF=BB=BFChristian Johansson [2021-11-28 08:22:48] wrote:
>> I believe tree-sitter is not suitable for proper parsing (it does not
>> support LR(1) for example)
>=20
> Really? AFAIK it uses a GLR parser and hence handles LR(1) and more.
>=20
>=20
> Stefan
>=20
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Wel=
l the GLR(k) algorithm might find a nondeterminstic route route in the gramm=
ar that a LR(k) do not find, if I want to know if a code is syntatically cor=
rect I would test it against the same type of parser the language uses, that=
is a deterministic parser
=
>
An intuit=
ive structure - Tree-sitter=E2=80=99s output is a concrete syntax tree; each node in the tree corresponds directly to a terminal or non=
-terminal symbol in the grammar. So in order to produce an easy-to-=
analyze tree, there should be a direct correspondence between the symbols in=
your grammar and the recognizable constructs in the language. This might se=
em obvious, but it is very different from the way that context-free grammars=
are often written in contexts like language specifications=
or Yacc=
/Bison p=
arsers.
> https:/=
/tree-sitter.github.io/tree-sitter/creating-parsers#the-grammar-dsl
<=
p style=3D"box-sizing: border-box;">This is a big issue because each version=
of a language grammar would need to be converted into tred-sitter form
<=
p style=3D"box-sizing: border-box;">
But anyways I don't see the issue with pluralism in the parser generato=
r space, why would one exclude the other?
Regards
Christian
28 nov. 2021 kl. 14:24 skrev Stefan Monnier <monnier@iro=
.umontreal.ca>:
=EF=BB=BF
Christian Johansson [2021-11-28 08:22:48] wrote:=
span>
I believe tree-sitter is not suitab=
le for proper parsing (it does not
support LR(1) for example)
=
Really? AFAIK it uses a GLR parser and hence handles LR(1) a=
nd more.
&nbs=
p; Stefan
=
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