Re: Iterating over all buffer lines

[Eric Abrahamsen <eric@ericabrahamsen.net>]

Le Wang <l26wang@gmail.com> writes:

> (while (not (= (point) (point-max)))
>   (message (buffer-substring-no-properties (point-at-bol) (point-at-eol)))
>   (forward-line 1))
>
>
> On Fri, Jan 18, 2013 at 4:55 AM, Sean McAfee <eefacm@gmail.com> wrote:
>> I have some code where I want to loop over all of the lines of text in a
>> buffer.  I had a prior solution that involved repeatedly searching for
>> the regexp "^.+$", but that seemed a little heavyweight.  Also, it only
>> found non-empty lines, and changing the "+" to a "*" to return all lines
>> causes an infinite loop.
>>
>> I just tried my hand at writing a general iterate-all-lines construct,
>> and came up with this:
>>
>> (loop for last-point = (point)
>>       while (= 0 (forward-line))
>>       for line = (buffer-substring-no-properties
>>                   last-point
>>                   (- (point) (if (bolp) 1 0)))
>>       ;; do something with line
>> )

Le Wang's solution is probably more idiomatic (for large-scale text
manipulation emacs seems better suited to working on a buffer than a
string), but you could also split the buffer substring on newlines and
map a function over the resulting list:

(mapcar (lambda (line)
	  (when line (manipulate-line line)))
	(split-string
	 (buffer-substring-no-properties (point-min) (point-max)) "\n"))