* How to translate `rx' expressions to `rx-to-string'?
@ 2014-07-31 14:37 Thorsten Jolitz
2014-07-31 15:07 ` Nicolas Richard
0 siblings, 1 reply; 3+ messages in thread
From: Thorsten Jolitz @ 2014-07-31 14:37 UTC (permalink / raw
To: help-gnu-emacs
Hi List,
this works fine
#+begin_src emacs-lisp
(format "%S"
(rx bol "foo_" (+ word) eol))
#+end_src
#+results:
: "^foo_[[:word:]]+$"
but its surprisingly difficult to translate it to `rx-to-string':
#+begin_src emacs-lisp
(format "%S"
(rx-to-string (list 'bol "foo_" '(+ word) 'eol)))
#+end_src
-> rx-form: Unknown rx form `bol'
When just using a string
#+begin_src emacs-lisp
(format "%S"
(rx "foo_"))
#+end_src
#+results:
: "foo_"
this is ok, but different:
#+begin_src emacs-lisp
(format "%S"
(rx-to-string "foo_"))
#+end_src
#+results:
: "\\(?:foo_\\)"
And this
#+begin_src emacs-lisp
(format "%S"
(rx-to-string (list "foo_" '+ 'word)))
#+end_src
or this
#+begin_src emacs-lisp
(format "%S"
(rx-to-string (list "foo_" '(+ word))))
#+end_src
both result in -> rx-form: Unknown rx form `foo_'
This works
#+begin_src emacs-lisp
(format "%S"
(rx-to-string "foo_" '(+ word)))
#+end_src
#+results:
: "foo_"
but ignores everything after the string.
Seems I did not get the syntax for function rx-to-string yet - any hints
would be welcome.
--
cheers,
Thorsten
^ permalink raw reply [flat|nested] 3+ messages in thread
* Re: How to translate `rx' expressions to `rx-to-string'?
2014-07-31 14:37 How to translate `rx' expressions to `rx-to-string'? Thorsten Jolitz
@ 2014-07-31 15:07 ` Nicolas Richard
2014-07-31 18:33 ` Thorsten Jolitz
0 siblings, 1 reply; 3+ messages in thread
From: Nicolas Richard @ 2014-07-31 15:07 UTC (permalink / raw
To: Thorsten Jolitz; +Cc: help-gnu-emacs
Thorsten Jolitz <tjolitz@gmail.com> writes:
> Seems I did not get the syntax for function rx-to-string yet - any hints
> would be welcome.
Read the code of rx.
(format "%S" (rx bol "foo_" (+ word) eol))
=> "\"^foo_[[:word:]]+$\""
(format "%S" (rx-to-string '(and bol "foo_" (+ word) eol) t))
=> "\"^foo_[[:word:]]+$\""
HTH,
--
Nico.
^ permalink raw reply [flat|nested] 3+ messages in thread
* Re: How to translate `rx' expressions to `rx-to-string'?
2014-07-31 15:07 ` Nicolas Richard
@ 2014-07-31 18:33 ` Thorsten Jolitz
0 siblings, 0 replies; 3+ messages in thread
From: Thorsten Jolitz @ 2014-07-31 18:33 UTC (permalink / raw
To: help-gnu-emacs
Nicolas Richard <theonewiththeevillook@yahoo.fr> writes:
> Thorsten Jolitz <tjolitz@gmail.com> writes:
>> Seems I did not get the syntax for function rx-to-string yet - any hints
>> would be welcome.
>
> Read the code of rx.
>
> (format "%S" (rx bol "foo_" (+ word) eol))
> => "\"^foo_[[:word:]]+$\""
>
> (format "%S" (rx-to-string '(and bol "foo_" (+ word) eol) t))
> => "\"^foo_[[:word:]]+$\""
>
> HTH,
Yes, that helps, thank you!
OTOH, just a bit more info and maybe one little example in the docstring
of `rx-to-string' would help a lot. This is supposed to be easier to use
than regular regexp syntax ...
--
cheers,
Thorsten
^ permalink raw reply [flat|nested] 3+ messages in thread
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