From: Andreas Politz <politza@fh-trier.de>
To: help-gnu-emacs@gnu.org
Subject: Re: Transposing Regular Expression
Date: Wed, 11 Nov 2009 22:45:17 +0100 [thread overview]
Message-ID: <87tyx0ka6q.fsf@fh-trier.de> (raw)
In-Reply-To: b40df352-3ed3-4f35-9304-86372ecddf9c@x5g2000prf.googlegroups.com
jrwats <jrwats@gmail.com> writes:
> Perl provides the transpose operator:
> =~ tr/abc/xyz/ not really a regular expression, but exchanges 'x' for
> 'a', 'y' for 'b', and 'z' for 'c' in the source string.
>
> My question is how to accomplish this in emacs. When only needing to
> tranpose 2 characters that need to replace each other, (the equivalent
> perl expression woud be =~ tr/ab/ba/ as an example, I could simply
> regexp replace 'a' with a unique letter or symbol, maybe '$' for
> instance, then replace all b's with a's and all $'s with b's. This
> obviously becomes unweildy after we start transposing more than 2
> characters. My question is, now that emacs provides fancy regexp
> replace clauses: \# for the number match, and arbitrary lisp
> expressions \,(some-lisp), etc, is there a way to accomplish this in
> one fell swoop via a very crazy regular expression find-replace? Also
> is there a list of meaningful regular expression search escape
> characters somewhere (like \#) ?
You can use literal backreferences (e.g. \1) in the replacement part of
interactive uses of replace-regexp. Combine that with expressions \,
and you could write a c-compiler in emacs-regexp/elisp.
The regular expression syntax is described in the elisp manual.
(info "(elisp)Regular Expressions")
-ap
next prev parent reply other threads:[~2009-11-11 21:45 UTC|newest]
Thread overview: 7+ messages / expand[flat|nested] mbox.gz Atom feed top
2009-11-11 17:25 Transposing Regular Expression jrwats
2009-11-11 20:51 ` harven
2009-11-11 21:45 ` Andreas Politz [this message]
2009-11-12 6:40 ` LanX
2009-11-16 12:16 ` Andreas Röhler
[not found] ` <mailman.10804.1258373854.2239.help-gnu-emacs@gnu.org>
2009-11-16 16:28 ` jrwats
2009-11-17 2:13 ` LanX
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