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From: "Pascal J. Bourguignon" <pjb@informatimago.com>
To: help-gnu-emacs@gnu.org
Subject: Re: About self-referential object
Date: Sat, 05 Jan 2013 01:07:53 +0100	[thread overview]
Message-ID: <87txqwh4py.fsf@kuiper.lan.informatimago.com> (raw)
In-Reply-To: mailman.16720.1357343280.855.help-gnu-emacs@gnu.org

"Drew Adams" <drew.adams@oracle.com> writes:

>> (setq foo '(nil)) => (nil)
>> (setcar foo foo)  => (#0)
>> 
>> It is an infinite recursion.  What does the `#0' mean here?  
>
> The Elisp manual is your friend.  There are no doubt several ways to look this
> up.  Start with `i' usually, which uses the indexes.
>
> If you don't find what you want using `i' then try searching: `C-s #0' finds an
> answer immediately in this case, in node `Output Function'.
>
> If you can find what you want by means other than using the indexes (`i'),
> consider reporting an Emacs bug to improve the index, explaining how you tried
> to find it.

Emacs lisp is really baroque.  
Why introduce #0 when #1=(#1#) can already denote it?


-- 
__Pascal Bourguignon__                     http://www.informatimago.com/
A bad day in () is better than a good day in {}.


  parent reply	other threads:[~2013-01-05  0:07 UTC|newest]

Thread overview: 9+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2013-01-04 23:32 About self-referential object Xue Fuqiao
2013-01-04 23:47 ` Drew Adams
2013-01-05  0:24   ` Xue Fuqiao
2013-01-05  0:55     ` Drew Adams
2013-01-05  1:26       ` Xue Fuqiao
2013-01-05  0:27   ` Xue Fuqiao
     [not found] ` <mailman.16720.1357343280.855.help-gnu-emacs@gnu.org>
2013-01-05  0:07   ` Pascal J. Bourguignon [this message]
2013-01-08 16:06     ` Stefan Monnier
     [not found] <mailman.16719.1357342389.855.help-gnu-emacs@gnu.org>
2013-01-04 23:40 ` Pascal J. Bourguignon

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