Regepxp-help: Replacing foo with bar but not foo.*

Regepxp-help: Replacing foo with bar but not foo.*

[Patrick Drechsler]

Hi,

how do I replace the term `foo' with `bar' when `foo' is followed
by a conditional term? Or what do I have to pass as argument to
`M-x replace-string'?

the rule I'm trying to imply is "replace foo if it is not
followed by a dot".

INPUT

foo jfkda
foo.bar fdjak

OUTPUT

fooMYREPLACEMENT jfkda
foo.bar fdjak


TIA

Patrick
-- 
"If you choke a smurf, what color does it turn?"

Re: Regepxp-help: Replacing foo with bar but not foo.*

[Ralf Angeli]

* Patrick Drechsler (2006-08-18) writes:

> the rule I'm trying to imply is "replace foo if it is not
> followed by a dot".
>
> INPUT
>
> foo jfkda
> foo.bar fdjak
>
> OUTPUT
>
> fooMYREPLACEMENT jfkda
> foo.bar fdjak

C-M-% foo\([^.]\) RET fooMYREPLACEMENT\1

-- 
Ralf

Re: Regepxp-help: Replacing foo with bar but not foo.*

[Eric Hanchrow]

and for what it's worth, if you want to write the regular expression
in Emacs Lisp code (as opposed to typing it directly to M-x
replace-regexp), you could use

        (rx "foo" (group (not (any "."))))

-- 
Rarely do we find men who willingly engage in hard, solid
thinking.  There is an almost universal quest for easy answers
and half-baked solutions.  Nothing pains some people more
than having to think.
        -- Martin Luther King, Jr.
        from "Strength to Love," 1963.

Re: Regepxp-help: Replacing foo with bar but not foo.*

[Patrick Drechsler]

Ralf Angeli wrote on 18 Aug 2006 21:34:04 MET:

> * Patrick Drechsler (2006-08-18) writes:
>
>> the rule I'm trying to imply is "replace foo if it is not
>> followed by a dot".
>>
>> INPUT
>>
>> foo jfkda
>> foo.bar fdjak
>>
>> OUTPUT
>>
>> fooMYREPLACEMENT jfkda
>> foo.bar fdjak
>
> C-M-% foo\([^.]\) RET fooMYREPLACEMENT\1

Ralf and Eric, thank you both for your answers!

Cheers

Patrick
-- 
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