() Howard McCay <howardmccay@yahoo.com>
() Wed, 5 Oct 2016 07:15:05 +0000 (UTC)

   (rose . (violet . buttercup))
   =
   (rose (violet . buttercup))

For Lisp (and Scheme), this relation does not hold.  To see for
yourself, in the *scratch* buffer, add:

 '(rose . (violet . buttercup))

and type ‘C-j’ (NB: single-quote at the beginning of the form).
You should see:

 (rose violet . buttercup)

Any change you propose to ‘read’ that assumes (or prescribes)
otherwise will be DOA.

-- 
Thien-Thi Nguyen -----------------------------------------------
 (defun responsep (type via)
   (case type
     (technical (eq 'mailing-list via))
     ...))                              748E A0E8 1CB8 A748 9BFA
--------------------------------------- 6CE4 6703 2224 4C80 7502