* [quite bad] (was: org 2 odt latex math are ignored)
2017-11-07 17:45 org 2 odt latex math are ignored Uwe Brauer
2017-11-07 17:49 ` Uwe Brauer
@ 2017-11-07 19:23 ` Uwe Brauer
1 sibling, 0 replies; 3+ messages in thread
From: Uwe Brauer @ 2017-11-07 19:23 UTC (permalink / raw)
To: emacs-orgmode
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>>> "Uwe" == Uwe Brauer <oub@mat.ucm.es> writes:
> Hi
Ok I followed the instructions in
http://orgmode.org/manual/Working-with-LaTeX-math-snippets.html#fn-1
First I tried the png solution
#+OPTIONS: tex:dvipng
I attach the solution together with the pdf file I generated converting
org to latex. The difference is huge. Then I installed
MathToWeb.
And
LaTeXML
Set #+OPTIONS: LaTeX:t
Mathtoweb was a bit better than png but not convert all of the
constructions.
Latexml confused to convert any math.
Quite annoying I'd say.
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#+OPTIONS: LaTeX:t
* Cálculo de la k
El calor perdido por el calorimetro esta dado por
\[
k= \left( \frac{M_f (T_e-T_f)}{(T_c-T_e)} -M_c \right)
\]
Los valores
están dado
\[M_c= 193.8 \qquad T_c=30.8 \quad T_e=23.1 \quad T_f=13.9 \quad M_f=192.7\]
\[T_1=23.1 \quad T_2=30.8\]
por lo tanto
\[
k=36.43 \quad\mbox{gr}
\]
* La incertidumbre de k
La incertidumbre de k esta dado por
\[
\Delta k =\left\vert \frac{(Te-Tf)}{(Tc-Te))} \right\vert \cdot \Delta
m_{2} +\Delta m_{1}+
\left\vert \frac{-(m2*(Te-Tf)}{(Tc-Te)}\right\vert^2\cdot \Delta t_{c}
\]
\[+
\left\vert \frac{m2*(Te-Tf}{(Tc-Te)}^2 \right\vert\cdot \Delta t_{e}
\left\vert \frac{-m2}{Tc-Te} \right\vert\cdot \Delta t_{c}
\] insertando
los valores nos da
\[
\Delta k =26.86\approx 26.9
\]
* La incertidumbre de k mediante derivadas
* Calculo de J
* La incertidumbre de Mc
La expresión para \(M_C\) esta dado por
\[
M_C =f(M_f,T_{e},T_c,T_f)= \frac{M_f (T_e-T_f)}{(T_c-T_e)} -k
\]
donde la
constante \(k\) no depende de \((T_c,T_e,T_f,M_f)\).
La incertidumbre de \(M_c\) esta dado por
\[
\Delta_{MC}= \sqrt{\left( \frac{\partial M_C}{\partial M_f}\Delta M_{f} \right)^2
+ \left( \frac{\partial M_C}{\partial T_C}\Delta T_{C} \right)^2
+ \left( \frac{\partial M_C}{\partial T_f}\Delta T_{f} \right)^2
+ \left( \frac{\partial M_C}{\partial T_e}\Delta T_{e} \right)^2}
\]
Donde las derivadas parciales están dadas por
\[
\sqrt{\frac{{\mathrm{dmf}}^2\, {\left(\mathrm{te} - \mathrm{tf}\right)}^2}{{\left(\mathrm{tc} - \mathrm{te}\right)}^2} + \frac{{\mathrm{dtf}}^2\, {\mathrm{mf}}^2}{{\left(\mathrm{tc} - \mathrm{te}\right)}^2} + \frac{{\mathrm{dte}}^2\, {\mathrm{mf}}^2\, {\left(\mathrm{tc} - \mathrm{tf}\right)}^2}{{\left(\mathrm{tc} - \mathrm{te}\right)}^4} + \frac{{\mathrm{dtc}}^2\, {\mathrm{mf}}^2\, {\left(\mathrm{te} - \mathrm{tf}\right)}^2}{{\left(\mathrm{tc} - \mathrm{te}\right)}^4}}
\]
\[
\frac{\partial M_C}{\partial M_f}= \frac{(T_e-T_f)}{(T_C-T_{e})}
\]
\[
\frac{\partial M_C}{\partial T_C}= -M_f\frac{(T_e-T_f)}{(T_C-T_{e})^2}
\]
\[
\frac{\partial M_C}{\partial T_f}= -M_f\frac{(T_e-T_f)}{(T_C-T_{e})}
\]
\[
\frac{\partial M_c}{\partial T_e}=M_f \frac{(T_C-T_e) -
(-1)(T_{e}-T_{f})}{(T_C-T_e)^{2}}=
M_f \frac{(T_C-T_f)}{(T_C-T_e)^{2}}
\]
Insertando los valores
\[
T_c=30.8 \quad T_e=23.1 \quad T_f=13.9 \quad M_f=192.7
\]
\[
\Delta M_1=0.1 \qquad \Delta M_2=0.01
\]
Nos da
\[
\Delta Mc= 6.7371 \approx 6.74
\]
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