elisp: how to pass a list argument to defun

elisp: how to pass a list argument to defun

[lalit mohan tripathi]

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Hi All,

   Could anyone tell me how to pass a list argument in elisp to a defun?

   I'm want to write a defun like this

(defun process-list-fn (list02, a, b, c)
  "This function prints the list02, a, b, c."
  (print list02)
  (print a)
  (print b)
  (print c))


I want to use it like this:

(setq list01 '("abc" "def" "xyz"))
(process-list-fn list01 10 20 30)

But I get the following error:

Debugger entered--Lisp error: (void-variable list02)
  (print list02)
  process-list-fn(("abc" "def" "xyz") 10 20 30)
  eval((process-list-fn list01 10 20 30))
  eval-last-sexp-1(nil)
  eval-last-sexp(nil)
  call-interactively(eval-last-sexp)
  recursive-edit()
  byte-code("Æ\b!^[,HG^[(B ^[,HH    ^[(B!^[,H\^[(Bn^[,C?

P.S. I'm able to pass the list to a function but that works when the defun
is defined with only one listarguement.

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Re: elisp: how to pass a list argument to defun

[Tassilo Horn]

"lalit mohan tripathi" <lalit.tripathi@gmail.com> writes:

Hi!

> (defun process-list-fn (list02, a, b, c)
>   "This function prints the list02, a, b, c."
>   (print list02)
>   (print a)
>   (print b)
>   (print c))
>
> (setq list01 '("abc" "def" "xyz"))
> (process-list-fn list01 10 20 30)
>
> But I get the following error:
>
> Debugger entered--Lisp error: (void-variable list02)

Lisp doesn't know the variable `list02', but it knows `list02,'. ;-)

In Lisp you don't separate the parameters with comma. Remove them and
you'll be fine.

Bye,
Tassilo
-- 
VI VI VI - The Roman Number Of The Beast

Re: elisp: how to pass a list argument to defun

[Pascal Bourguignon]

"lalit mohan tripathi" <lalit.tripathi@gmail.com> writes:

> Hi All,
>    Could anyone tell me how to pass a list argument in elisp to a defun?
>    I'm want to write a defun like this
> (defun process-list-fn (list02, a, b, c)
>   "This function prints the list02, a, b, c."
>   (print list02)
>   (print a)
>   (print b)
>   (print c))
> I want to use it like this:
> (setq list01 '("abc" "def" "xyz"))
> (process-list-fn list01 10 20 30)


(defun process-list-fn (list02, a, b, c)
  "This function prints the list02, a, b, c."
  (print list02,)
  (print a,)
  (print b,)
  (print c))


(process-list-fn 'list01 10 20 30)

prints:
list01

10

20

30

returns:
30

-- 
__Pascal Bourguignon__                     http://www.informatimago.com/

CAUTION: The mass of this product contains the energy equivalent of
85 million tons of TNT per net ounce of weight.

Re: elisp: how to pass a list argument to defun

[Le Wang]

lalit mohan tripathi wrote:
> Hi All,
>
>    Could anyone tell me how to pass a list argument in elisp to a defun?
>
>    I'm want to write a defun like this
>
> (defun process-list-fn (list02, a, b, c)
>   "This function prints the list02, a, b, c."
>   (print list02)
>   (print a)
>   (print b)
>   (print c))
>
>
> I want to use it like this:
>
> (setq list01 '("abc" "def" "xyz"))
> (process-list-fn list01 10 20 30)
>
> But I get the following error:
>
> Debugger entered--Lisp error: (void-variable list02)
>   (print list02)
>   process-list-fn(("abc" "def" "xyz") 10 20 30)
>   eval((process-list-fn list01 10 20 30))
>   eval-last-sexp-1(nil)
>   eval-last-sexp(nil)
>   call-interactively(eval-last-sexp)
>   recursive-edit()
>   byte-code("?\b!?HG ?HH    !?H\n?C?
>
> P.S. I'm able to pass the list to a function but that works when the defun
> is defined with only one listarguement.

remove the commas from your defun formal parameters list.

--
Le