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From: Eli Zaretskii <eliz@gnu.org>
To: Lars Ingebrigtsen <larsi@gnus.org>
Cc: layer@franz.com, benjamin.benninghofen@airbus.com,
	32729@debbugs.gnu.org, 32728@debbugs.gnu.org
Subject: bug#32728: bug#32729: Xemacs 23 times as fast as GNU Emacs
Date: Mon, 14 Oct 2019 12:15:09 +0300	[thread overview]
Message-ID: <8336fvk7s2.fsf@gnu.org> (raw)
In-Reply-To: <87v9sriv0k.fsf@gnus.org> (message from Lars Ingebrigtsen on Mon,  14 Oct 2019 10:36:11 +0200)

> From: Lars Ingebrigtsen <larsi@gnus.org>
> Cc: benjamin.benninghofen@airbus.com,  layer@franz.com,
>   32729@debbugs.gnu.org,  32728@debbugs.gnu.org
> Date: Mon, 14 Oct 2019 10:36:11 +0200
> 
> Eli Zaretskii <eliz@gnu.org> writes:
> 
> > I don't understand what would trigger these callbacks, and how do you
> > specify the region in advance, without knowing what will be inserted.
> 
> accept_process_output inserts the data into the buffer and then calls
> the callback with the region in question.  Well,
> read_and_dispose_of_process_output, I guess...

Filter functions are called even if the Lisp program never calls
accept-process-output, so your proposal doesn't seem to be equivalent
to what we have now, right?

OTOH, if one has to call accept-process-output, then why do we need
callbacks?  Just extend accept-process-output to call a function with
the received output.  No?

> > Without understanding this, I don't think I see the utility, and most
> > important: why this would be faster.
> 
> It would avoid creating (and garbaging) the strings.

I'm not sure I see how.

The way it works now is that we get the process output as a C string;
we then decode it and make a Lisp string from the result of decoding;
and then we invoke the filter with that Lisp string.  (If the filter
is nil, we invoke internal-default-process-filter instead, but it
still gets the text as a string.)

Which part(s) of this will be avoided under your proposal?

> > Btw, unlike what I originally implied, the default filter also
> > receives a Lisp string, so the question why by default reading dd
> > output is so much faster than when you define a non-default filter
> > function still stands.
> 
> Oh!  That is curious indeed.  Are the Lisp_Object strings somehow
> ... special here when they never leave C land?

No, I don't think so.

> The speed differential is completely repeatable...  hm...  Is the
> only difference that gc isn't given a chance to run in the
> non-filter case?

You could test that hypothesis by setting gc-cons-threshold to a very
high value.

Bottom line: I think we must understand better what takes the time in
your last test case, before we discuss solutions.  I'd start by
profiling that with "M-x profiler-start".





  reply	other threads:[~2019-10-14  9:15 UTC|newest]

Thread overview: 18+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2018-09-13 13:32 bug#32729: Xemacs 23 times as fast as GNU Emacs Benninghofen, Benjamin Dr.
2019-10-12  3:57 ` Lars Ingebrigtsen
2019-10-12  7:39   ` bug#32728: " Eli Zaretskii
2019-10-12 17:55     ` Lars Ingebrigtsen
2019-10-13  8:13       ` bug#32728: " Eli Zaretskii
2019-10-13 17:36         ` Lars Ingebrigtsen
2019-10-14  8:18           ` Eli Zaretskii
2019-10-14  8:36             ` bug#32728: " Lars Ingebrigtsen
2019-10-14  9:15               ` Eli Zaretskii [this message]
2019-10-13 17:47         ` Lars Ingebrigtsen
2019-10-13 18:46           ` Eli Zaretskii
2019-10-14  8:54             ` Lars Ingebrigtsen
2019-10-14 10:18               ` bug#32728: " Eli Zaretskii
2019-10-25  6:38               ` Benninghofen, Benjamin Dr.
2019-10-25  7:00                 ` Eli Zaretskii
2019-10-13 10:49   ` Phil Sainty
2019-10-13 17:24     ` bug#32728: " Lars Ingebrigtsen
2019-10-13 18:44       ` Eli Zaretskii

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