Emacs regexp problem

Emacs regexp problem

[mailpitches]

X-No-Archive:yes

Hello, I'm doing an emacs replace-regexp and the regexp behaves
differently from how it behaves in Python, and also differently from
how I expect.

I'm trying to add quotes around the parameter in a function call.
I.e.:
func(param) should be converted to func('param')

I use the following command:
M-x replace-regexp [enter] get\((.*)\) [enter] get('\1')) [enter]

and the result is func(param) is converted to func('(param)')

Why are those extra parentheses appearing in there; is this an error
on emacs' part?

Thanks

Re: Emacs regexp problem

[Pascal Bourguignon]

"mailpitches@email.com" <mailpitches@email.com> writes:

> Hello, I'm doing an emacs replace-regexp and the regexp behaves
> differently from how it behaves in Python, and also differently from
> how I expect.
>
> I'm trying to add quotes around the parameter in a function call.
> I.e.:
> func(param) should be converted to func('param')
>
> I use the following command:
> M-x replace-regexp [enter] get\((.*)\) [enter] get('\1')) [enter]
>
> and the result is func(param) is converted to func('(param)')
>
> Why are those extra parentheses appearing in there; is this an error
> on emacs' part?

Read the doc! (info "(emacs)Regexps")

emacs regexp are more like BRE than ERE in this respect.


Use: M-x replace-regexp RET get(\(.*\)) RET get('\1')) RET

-- 
__Pascal Bourguignon__                     http://www.informatimago.com/

READ THIS BEFORE OPENING PACKAGE: According to certain suggested
versions of the Grand Unified Theory, the primary particles
constituting this product may decay to nothingness within the next
four hundred million years.

Re: Emacs regexp problem

[Joel J. Adamson]

"mailpitches@email.com" <mailpitches@email.com> writes:

[...]


> func(param) should be converted to func('param')
>
> I use the following command:
> M-x replace-regexp [enter] get\((.*)\) [enter] get('\1')) [enter]
>
> and the result is func(param) is converted to func('(param)')
>
> Why are those extra parentheses appearing in there

They're your parentheses: in emacs \(...\) makes groups, rather than
(...), so your second un-escaped set of parentheses is getting matched
and ending up in the replacement ('\1').

> ; is this an error on emacs' part?

Not really ;)

Joel

-- 
Joel J. Adamson
Biostatistician
Pediatric Psychopharmacology Research Unit
Massachusetts General Hospital
Boston, MA  02114
(617) 643-1432
(303) 880-3109

Re: Emacs regexp problem

[Xah Lee]

For a basic coverage of the diff between emacs and perl/python's
regex, see:

 http://xahlee.org/emacs/emacs_regex.html

  Xah
  xah@xahlee.org
∑ http://xahlee.org/

☄

On Jan 29, 10:00 am, "mailpitc...@email.com" <mailpitc...@email.com>
wrote:
> X-No-Archive:yes
>
> Hello, I'm doing an emacs replace-regexp and the regexp behaves
> differently from how it behaves in Python, and also differently from
> how I expect.
>
> I'm trying to add quotes around the parameter in a function call.
> I.e.:
> func(param) should be converted to func('param')
>
> I use the following command:
> M-x replace-regexp [enter] get\((.*)\) [enter] get('\1')) [enter]
>
> and the result is func(param) is converted to func('(param)')
>
> Why are those extra parentheses appearing in there; is this an error
> on emacs' part?
>
> Thanks

Re: Emacs regexp problem

[Tim X]

Pascal Bourguignon <pjb@informatimago.com> writes:

> "mailpitches@email.com" <mailpitches@email.com> writes:
>
>> Hello, I'm doing an emacs replace-regexp and the regexp behaves
>> differently from how it behaves in Python, and also differently from
>> how I expect.
>>
>> I'm trying to add quotes around the parameter in a function call.
>> I.e.:
>> func(param) should be converted to func('param')
>>
>> I use the following command:
>> M-x replace-regexp [enter] get\((.*)\) [enter] get('\1')) [enter]
>>
>> and the result is func(param) is converted to func('(param)')
>>
>> Why are those extra parentheses appearing in there; is this an error
>> on emacs' part?
>
> Read the doc! (info "(emacs)Regexps")
>
> emacs regexp are more like BRE than ERE in this respect.
>
>
> Use: M-x replace-regexp RET get(\(.*\)) RET get('\1')) RET

Isn't there an extra ) at the end which shouldn't be there?

Also, note the RE's are greedy. This means you probably want to modify
the \(.*\) so that it only matches on the smallest possible match or you
could get odd results if there are any lines with multiple get()s in
them.

Tim
>
> -- 
> __Pascal Bourguignon__                     http://www.informatimago.com/
>
> READ THIS BEFORE OPENING PACKAGE: According to certain suggested
> versions of the Grand Unified Theory, the primary particles
> constituting this product may decay to nothingness within the next
> four hundred million years.

-- 
tcross (at) rapttech dot com dot au