Sure, but it reinterprets the integer as a *Lisp_Symbol to get at the actual struct correct? Or am I misunderstanding how this works?
On Oct 26, 2022, 10:00 AM -0600, Eli Zaretskii <eliz@gnu.org>, wrote:
> > Date: Wed, 26 Oct 2022 09:40:30 -0600
> > From: Troy Hinckley <troyhinckley@gmail.com>
> >
> > I have been reading through the C source to try and learn it and understand it better. I saw in Changeling.13 an
> > entry From Paul Eggert on 2015-01-05 with “Use 0 for Qnil” As a fix for Bug#15880. How does this work in
> > practice? It looks like symbols are just pointers, but 0 would not be a valid pointer. I don’t see any special code
> > for handling the null case.
>
> Symbols are not pointers, they have the same C type as any other
> Lisp_Object. If Lisp_Object is represented by an integer number, then
> zero is a valid integer number as well.
>