Re: regex and case-fold-search problem

["Eli Zaretskii" <eliz@is.elta.co.il>]

> From: Richard Stallman <rms@gnu.org>
> Date: Fri, 30 Aug 2002 15:19:14 -0400
> 
>     I think we all know that is the right behaviour, and at
>     least for ASCII, the latest code works as that.  Perhpas, we
>     should make Emacs work correctly also for Latin-1 chars,
>     because in emacs-unicode also, they have the same code
>     order.
> 
> What about for Latin-2 characters?  Will those regexp ranges
> change their meaning in emacs-unicode?

Yes.  Latin-2 characters have different order in Unicode than in
8859-2.  Those characters which are common to Latin-2 and Latin-1 are
in the same order, but those which aren't have different places.  The
same goes for all the other Latin-N characters where N != 1.

We could have some code to map a range specified by a Lisp program
into a range of internal character codepoints (in Unicode Emacs, the
latter would be Unicode codepoints).  We could make this code depend
on some user variable that states the external ordering meant by the
application.  For example, Cyrillic users could tell Emacs that [A-Z]
was intended to work as in KOI8-R or as in 8859-5.

Would something like that work?