Re: `call-interactively' only the first time

[wenbinye@gmail.com]

You didn't provide the real code, I assume you may make mistake when
use
the function in parameter, which is named g in you pseudo code. You
should
use funcall function.
Another question is how do you restore the argument when called
interactively first time?

(defun foo (arg)
  (interactive "sGive me a string: ")
  (message "foo: %S" arg))

(defun bar (func)
    (message "first call: ")
    (call-interactively func)
    (message "call again: ")
    (funcall func "efg"))

;; use like this:
(bar 'foo)

augukarl@yahoo.se wrote:
> wenbinye@gmail.com skrev:
> > Can you give the definition of the function?
>
> Here is the pseudo code for the function I want to define:
>
> (defun f (g)  ;; g is an interactive function.
>   ;; Call g interactively.
>   ;; Call g non-interactively with the parameters (specified by
>   ;; the user) in the command above.
>   )
> 
> Is this clear enough?
> 
> 
> Thanks,
> 
> August