From: zghuang@bloomberg.net (Z. Huang)
Subject: list conversion
Date: 06 May 2003 15:46:49 -0400 [thread overview]
Message-ID: <yq0cznlz26za.fsf@blinky.bloomberg.com> (raw)
Given a list ("first" "second" "third"). I'd to convert it to a
a new list:
(("" . "first")
("" . "second")
("" . "third"))
The following lisp code was intended for this purpose, but not working. It
looks that I missed some very basic stuff (I rarely code in lisp). Can
anyone point out what is wrong? Thanks in advance.
(defun list-conversion (arg)
(let ((l arg) (new-list ()))
(while l
(append new-list (list "" . (car l))))
(setq l (cdr l))))
next reply other threads:[~2003-05-06 19:46 UTC|newest]
Thread overview: 4+ messages / expand[flat|nested] mbox.gz Atom feed top
2003-05-06 19:46 Z. Huang [this message]
2003-05-06 20:04 ` list conversion Barry Margolin
2003-05-06 20:09 ` Jesper Harder
-- strict thread matches above, loose matches on Subject: below --
2003-05-06 19:33 Zhengao. Huang
Reply instructions:
You may reply publicly to this message via plain-text email
using any one of the following methods:
* Save the following mbox file, import it into your mail client,
and reply-to-all from there: mbox
Avoid top-posting and favor interleaved quoting:
https://en.wikipedia.org/wiki/Posting_style#Interleaved_style
List information: https://www.gnu.org/software/emacs/
* Reply using the --to, --cc, and --in-reply-to
switches of git-send-email(1):
git send-email \
--in-reply-to=yq0cznlz26za.fsf@blinky.bloomberg.com \
--to=zghuang@bloomberg.net \
/path/to/YOUR_REPLY
https://kernel.org/pub/software/scm/git/docs/git-send-email.html
* If your mail client supports setting the In-Reply-To header
via mailto: links, try the mailto: link
Be sure your reply has a Subject: header at the top and a blank line
before the message body.
This is a public inbox, see mirroring instructions
for how to clone and mirror all data and code used for this inbox;
as well as URLs for read-only IMAP folder(s) and NNTP newsgroup(s).