From: lawrence mitchell <wence@gmx.li>
Subject: Re: How to: 96 bit Date-time arithmetic?
Date: Sat, 31 Aug 2002 21:49:08 +0100 [thread overview]
Message-ID: <wkptvyah4r.fsf@ID-97657.usr.dfncis.de> (raw)
In-Reply-To: un22ak65c7svc3@corp.supernews.com
Siegfried Heintze wrote:
> While I am still curious about 96 bit arithmetic, here an alternative
> attempt. Why does not it work?
> (setq x (decode-time (current-time)))
> (setq y (list (car x) (cadr x) (caddr x) (1- (cadddr x))
> (nth 5 x) (nth 6 x) (nth 7 x)(nth 8 x) ))
^ (nth 4 x)
> (apply 'encode-time x) ; no error
> (apply 'encode-time y) ; error -- why?
in `nth', N counts from zero.
Hence you want (nth 4 x) before (nth 5 x)
Notice that:
(length x)
=> 9
(length y)
=> 8
I'd probably do
(setcar (nthcdr 3 x) (1- (nth 3 x)))
instead, as it's somewhat easier to read.
On another note of style, you probably don't want to use setq
unless you've already bound x in a `let' form, or x is indeed a
global variable. e.g.
(let ((x (decode-time (current-time))))
(setcar (nthcdr 3 x) (1- (nth 3 x)))
x)
To return the modified value of x.
--
lawrence mitchell <wence@gmx.li>
next prev parent reply other threads:[~2002-08-31 20:49 UTC|newest]
Thread overview: 5+ messages / expand[flat|nested] mbox.gz Atom feed top
2002-08-31 15:39 How to: 96 bit Date-time arithmetic? Siegfried Heintze
2002-08-31 18:21 ` Siegfried Heintze
2002-08-31 20:49 ` lawrence mitchell [this message]
2002-09-04 7:57 ` Christian Lemburg
2002-09-04 13:58 ` Alan Shutko
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