Re: Decode the octets with hexadecimal values.

[Platon Pronko <platon7pronko@gmail.com>]

On 2023-05-20 14:55, Hongyi Zhao wrote:
> Hi here,
> 
> According to one of the comments here [1], I try to read the related
> discussion here [2], but al.howardknight.net doesn't do any decoding
> of the articles and I will see some non-human readable stuff, for
> example:
> 
> the shell first will do the same and then tell the kernel by means=20
> of the system service =E2=80=9Cdup2=E2=80=9D to copy the contents of the en=
> try #1 to=20
> the entry #2.=C2=A0 Now two entries in the process' file descriptor=20
> table=C2=A0=E2=80=93 #1 and #2=C2=A0=E2=80=93 refer to the opened file =E2=
> =80=9Coutput.txt=E2=80=9D.
> 
> So, I would like to know how to decode the octets with hexadecimal
> values with the help of Emacs.
> 
> [1] https://groups.google.com/g/comp.unix.shell/c/xXqxHrIchqg
> [2] http://al.howardknight.net/?ID=165151671300
> 
> Best,
> Zhao

Hi!

That looks like quoted-printable encoding. I don't know how to decode that in Emacs,
but here's an example of how you can do that in Python:

import codecs
s = """
the shell first will do the same and then tell the kernel by means=20
of the system service =E2=80=9Cdup2=E2=80=9D to copy the contents of the en=
try #1 to=20
the entry #2.=C2=A0 Now two entries in the process' file descriptor=20
table=C2=A0=E2=80=93 #1 and #2=C2=A0=E2=80=93 refer to the opened file =E2=
=80=9Coutput.txt=E2=80=9D.
"""
print(codecs.decode(s.encode("utf8"), "QUOTED-PRINTABLE").decode("utf8").strip())

-- 
Best regards,
Platon Pronko
PGP 2A62D77A7A2CB94E