Re: Replace regexp question

[Leandro Marcolino <leandromarcolino@gmail.com>]

Oh, I think I got it. I nested the groups like: "<span lang=ZH-CN
>\(\(&#31169;\)+\)</span><span lang=PT-BR -> <span lang=ZH-CN
style='letter-spacing:-5px'>\1</span><span lang=PT-BR". That works!.. :)

Thanks!..

Leandro


On Sat, Jun 8, 2013 at 9:46 AM, Leandro Marcolino <
leandromarcolino@gmail.com> wrote:

> Just to be clear, when I say replace by: "<span lang=ZH-CN
> style='letter-spacing:-5px'>&#31169;&#31169;&#31169;</span><span
> lang=PT-BR", I mean that the number of &#31169; must be the same as in
> the original text.
>
> Thanks!..
>
> Leandro
>
>
> On Sat, Jun 8, 2013 at 9:44 AM, Leandro Marcolino <
> leandromarcolino@gmail.com> wrote:
>
>> Thank you very much for all the replies!.. :) But, maybe my example was
>> too simplistic.... hehe
>>
>> I want to file occurrences of "<span lang=ZH-CN
>> >&#31169;&#31169;&#31169;</span><span lang=PT-BR", but the number of
>> &#31169; can be one or more, and replae by "<span lang=ZH-CN
>> style='letter-spacing:-5px'>&#31169;&#31169;&#31169;</span><span
>> lang=PT-BR".
>>
>> If I try: "<span lang=ZH-CN >\(&#31169;+\)</span><span lang=PT-BR ->
>> <span lang=ZH-CN style='letter-spacing:-5px'>\1</span><span lang=PT-BR"
>> then no pattern is found
>> If I try: "<span lang=ZH-CN >\(&#31169;\)+</span><span lang=PT-BR ->
>> <span lang=ZH-CN style='letter-spacing:-5px'>\1</span><span lang=PT-BR"
>> then the sequence of &#31169; changes to a single &#31169;.
>>
>> Is there a way to solve this problem?...
>>
>> Thank you very much!..
>>
>> Thanks,
>> Leandro
>>
>>
>> On Sat, Jun 8, 2013 at 8:11 AM, Pascal J. Bourguignon [via Emacs] <
>> ml-node+s1067599n288199h15@n5.nabble.com> wrote:
>>
>>> Leandro Marcolino <[hidden email]<http://user/SendEmail.jtp?type=node&node=288199&i=0>>
>>> writes:
>>>
>>> > Hello, all!..
>>> >
>>> > I am trying to add text after multiple occurrences of a group, but it
>>> is not
>>> > working. For example, if I try to change the following: "aaaaaa" to
>>> > "aaaaaab", I end up with "ab"...
>>> >
>>> > I am looking for the regexp: \(a\)+ and I replace by \1b. But then the
>>> > sequence of a's is reduced to a single "a". How can I make the final
>>> text
>>> > have the same number of occurrences of the group as the original
>>> text?..
>>>
>>> That's because there is a single a inside \( \)!
>>> Try: \(a+\) -> \1b
>>>
>>> --
>>> __Pascal Bourguignon__                     http://www.informatimago.com/
>>> A bad day in () is better than a good day in {}.
>>> You can take the lisper out of the lisp job, but you can't take the lisp
>>> out
>>> of the lisper (; -- antifuchs
>>>
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