Re: Output hash-table from a function

[Yuri Khan <yuri.v.khan@gmail.com>]

On Sun, 22 Sept 2024 at 22:16, Heime <heimeborgia@protonmail.com> wrote:

> > > (defun xiakos-anctr (fpln)
> > >
> > > (if (hash-table-p fpln)
> > >
> > > (let ( (anctr (make-hash-table :test 'equal)) )
> > > (maphash (lambda (waypt dirpath)
> > > (puthash
> > > waypt (not (file-directory-p dirpath))
> > > anctr))
> > > fpln)) ))
> >
> > Hint 1: What does your function to return right now?
>
> xiakos-anctr is certainly not returning a hash table, as I wanted

You are not answering the question. I am asking it because by
answering it you will get closer to understanding the root of your
issue. So, what *is* it returning?

> > Hint 2: You’ve created a hash table, bound it to a local variable,
> > then did a bunch of mutations to that hash table, and then what?
>
> I want to call the function and store the hash table result in a let statement
>
> (let ( (anctr (xiakos-anctr flpn)) )

This assumes xiakos-anctr returns the hash table. But, as you have
seen, it does not return it. So what *happens* to the hash table you
created in xiakos-anctr?