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From: Arthur Miller <arthur.miller@live.com>
To: Hans Lonsdale <hanslonsdale@mailfence.com>
Cc: Help Gnu Emacs <help-gnu-emacs@gnu.org>
Subject: Re: Finding repetitions of 8-tuples
Date: Sun, 01 Jan 2023 16:13:50 +0100	[thread overview]
Message-ID: <AM9PR09MB4977292E2D6088645EBE316C96F69@AM9PR09MB4977.eurprd09.prod.outlook.com> (raw)
In-Reply-To: <1399831366.706043.1672506045023@ichabod.co-bxl> (Hans Lonsdale's message of "Sat, 31 Dec 2022 18:00:45 +0100 (CET)")

Hans Lonsdale <hanslonsdale@mailfence.com> writes:

> I have 16 collections of 8 numbers
>
> (11 12 11 44 11 12 11 23)
> (12 21 11 44 11 12 11 23)
> and so on
>
> I want to find whether there are repetitions of each 8-tuple.
> The order in which the numbers occur is not important.

Have you looked at "lists as sets" chapter in the manual?

There is a 'cl-subsetp' you could start with:

  cl-subsetp is an autoloaded native-compiled Lisp function in ‘cl-seq.el’.

  (cl-subsetp LIST1 LIST2 [KEYWORD VALUE]...)

  Return true if LIST1 is a subset of LIST2.
  I.e., if every element of LIST1 also appears in LIST2.

  Keywords supported:  :test :test-not :key


(defvar l1 '(11 12 11 44 11 12 11 23))
(defvar l2 '(12 21 11 44 11 12 11 23))

(cl-subsetp l1 l2) ;; returns t

However there is a slight problem since it tests for the subset:

(defvar l3 '(12 21 11 44 11 12 11))

(cl-subsetp l3 l2) ;; returns t also

(and (cl-subsetp l3 l2)
     (= (length l3) (length l2))) ;; should do


Alternatively there functions to test membership, so you could easily roll your
own little defun with 'member' or something else.



  reply	other threads:[~2023-01-01 15:13 UTC|newest]

Thread overview: 8+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2022-12-31 17:00 Finding repetitions of 8-tuples Hans Lonsdale
2023-01-01 15:13 ` Arthur Miller [this message]
2023-01-01 16:00   ` Ruijie Yu via Users list for the GNU Emacs text editor
2023-01-01 16:39   ` Yuri Khan
2023-01-01 17:08     ` Hans Lonsdale
2023-01-01 15:16 ` Ruijie Yu via Users list for the GNU Emacs text editor
2023-01-01 15:38   ` Hans Lonsdale
2023-01-08  4:39 ` Emanuel Berg

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