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* elisp: how to pass a list argument to defun
@ 2006-06-28  9:36 lalit mohan tripathi
  0 siblings, 0 replies; 4+ messages in thread
From: lalit mohan tripathi @ 2006-06-28  9:36 UTC (permalink / raw)



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Hi All,

   Could anyone tell me how to pass a list argument in elisp to a defun?

   I'm want to write a defun like this

(defun process-list-fn (list02, a, b, c)
  "This function prints the list02, a, b, c."
  (print list02)
  (print a)
  (print b)
  (print c))


I want to use it like this:

(setq list01 '("abc" "def" "xyz"))
(process-list-fn list01 10 20 30)

But I get the following error:

Debugger entered--Lisp error: (void-variable list02)
  (print list02)
  process-list-fn(("abc" "def" "xyz") 10 20 30)
  eval((process-list-fn list01 10 20 30))
  eval-last-sexp-1(nil)
  eval-last-sexp(nil)
  call-interactively(eval-last-sexp)
  recursive-edit()
  byte-code("Æ\b!^[,HG^[(B ^[,HH    ^[(B!^[,H\^[(Bn^[,C?

P.S. I'm able to pass the list to a function but that works when the defun
is defined with only one listarguement.

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     [not found] <mailman.3433.1151487404.9609.help-gnu-emacs@gnu.org>
2006-06-28 10:03 ` elisp: how to pass a list argument to defun Tassilo Horn
2006-06-28 13:55 ` Pascal Bourguignon
2006-06-28 20:59 ` Le Wang
2006-06-28  9:36 lalit mohan tripathi

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