From: Tassilo Horn <heimdall@uni-koblenz.de>
Subject: Re: elisp: how to pass a list argument to defun
Date: Wed, 28 Jun 2006 12:03:37 +0200 [thread overview]
Message-ID: <87r719tx52.fsf@baldur.nicundtas.de> (raw)
In-Reply-To: mailman.3433.1151487404.9609.help-gnu-emacs@gnu.org
"lalit mohan tripathi" <lalit.tripathi@gmail.com> writes:
Hi!
> (defun process-list-fn (list02, a, b, c)
> "This function prints the list02, a, b, c."
> (print list02)
> (print a)
> (print b)
> (print c))
>
> (setq list01 '("abc" "def" "xyz"))
> (process-list-fn list01 10 20 30)
>
> But I get the following error:
>
> Debugger entered--Lisp error: (void-variable list02)
Lisp doesn't know the variable `list02', but it knows `list02,'. ;-)
In Lisp you don't separate the parameters with comma. Remove them and
you'll be fine.
Bye,
Tassilo
--
VI VI VI - The Roman Number Of The Beast
next parent reply other threads:[~2006-06-28 10:03 UTC|newest]
Thread overview: 4+ messages / expand[flat|nested] mbox.gz Atom feed top
[not found] <mailman.3433.1151487404.9609.help-gnu-emacs@gnu.org>
2006-06-28 10:03 ` Tassilo Horn [this message]
2006-06-28 13:55 ` elisp: how to pass a list argument to defun Pascal Bourguignon
2006-06-28 20:59 ` Le Wang
2006-06-28 9:36 lalit mohan tripathi
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