* replace-regexp in lisp function
@ 2010-01-18 9:29 Sven Garbade
0 siblings, 0 replies; 5+ messages in thread
From: Sven Garbade @ 2010-01-18 9:29 UTC (permalink / raw)
To: help-gnu-emacs
Hallo List,
I frequently use the following regular-regexp:
M-x replace-regexp <RET> \(<<\) <RET> \1cn\,(+ (line-number-at-pos) \#)
to replace "<<" with "<<cn=line number". I tried to write a function
;; add chunk number
(defun add-chunk-number ()
(interactive)
(query-replace-regexp "\(<<\)" "\1cn\,(+ (line-number-at-pos) \#)")
)
to save typing, but this does not work. What did I wrong?
Thanks, Sven
^ permalink raw reply [flat|nested] 5+ messages in thread
* Re: replace-regexp in lisp function
[not found] <mailman.1632.1263815405.18930.help-gnu-emacs@gnu.org>
@ 2010-01-18 13:01 ` David Kastrup
2010-01-18 14:06 ` Sven Garbade
2010-01-18 13:11 ` Pascal J. Bourguignon
1 sibling, 1 reply; 5+ messages in thread
From: David Kastrup @ 2010-01-18 13:01 UTC (permalink / raw)
To: help-gnu-emacs
Sven Garbade <sfgarbade@googlemail.com> writes:
> Hallo List,
>
> I frequently use the following regular-regexp:
>
> M-x replace-regexp <RET> \(<<\) <RET> \1cn\,(+ (line-number-at-pos) \#)
>
> to replace "<<" with "<<cn=line number". I tried to write a function
>
> ;; add chunk number
> (defun add-chunk-number ()
> (interactive)
> (query-replace-regexp "\(<<\)" "\1cn\,(+ (line-number-at-pos) \#)")
> )
>
> to save typing, but this does not work. What did I wrong?
Lisp string syntax needs additional quoting for regexps, and things like
\, and \# are not supported outside of interactive use.
I recommend that you first give your command interactively, then use C-x
Esc Esc to get at the corresponding Lisp verbiage.
--
David Kastrup
^ permalink raw reply [flat|nested] 5+ messages in thread
* Re: replace-regexp in lisp function
[not found] <mailman.1632.1263815405.18930.help-gnu-emacs@gnu.org>
2010-01-18 13:01 ` replace-regexp in lisp function David Kastrup
@ 2010-01-18 13:11 ` Pascal J. Bourguignon
1 sibling, 0 replies; 5+ messages in thread
From: Pascal J. Bourguignon @ 2010-01-18 13:11 UTC (permalink / raw)
To: help-gnu-emacs
Sven Garbade <sfgarbade@googlemail.com> writes:
> Hallo List,
>
> I frequently use the following regular-regexp:
>
> M-x replace-regexp <RET> \(<<\) <RET> \1cn\,(+ (line-number-at-pos) \#)
>
> to replace "<<" with "<<cn=line number". I tried to write a function
>
> ;; add chunk number
> (defun add-chunk-number ()
> (interactive)
> (query-replace-regexp "\(<<\)" "\1cn\,(+ (line-number-at-pos) \#)")
> )
>
> to save typing, but this does not work. What did I wrong?
You don't understand the syntax of strings.
How many characters are there in "\(" ?
How many characters are there in "\n" ?
How many characters are there in "\\(" ?
How many characters are there in "\\n" ?
--
__Pascal Bourguignon__ http://www.informatimago.com/
^ permalink raw reply [flat|nested] 5+ messages in thread
* Re: replace-regexp in lisp function
2010-01-18 13:01 ` replace-regexp in lisp function David Kastrup
@ 2010-01-18 14:06 ` Sven Garbade
2010-01-18 14:11 ` David Kastrup
0 siblings, 1 reply; 5+ messages in thread
From: Sven Garbade @ 2010-01-18 14:06 UTC (permalink / raw)
To: David Kastrup; +Cc: help-gnu-emacs
Hi,
many thanks. C-x Esc Esc gave me:
(query-replace-regexp "\\(<<\\)"
(quote (replace-eval-replacement concat "\\1cn" (replace-quote (+
(line-number-at-pos) replace-count)) ",")) nil
(if (and transient-mark-mode mark-active) (region-beginning))
(if (and transient-mark-mode mark-active) (region-end)))
which works inside my function. Looks quite complicate for me...
Are there any recommended documents / books for an elisp newbie?
Thanks, Sven
2010/1/18 David Kastrup <dak@gnu.org>:
> Sven Garbade <sfgarbade@googlemail.com> writes:
>
>> Hallo List,
>>
>> I frequently use the following regular-regexp:
>>
>> M-x replace-regexp <RET> \(<<\) <RET> \1cn\,(+ (line-number-at-pos) \#)
>>
>> to replace "<<" with "<<cn=line number". I tried to write a function
>>
>> ;; add chunk number
>> (defun add-chunk-number ()
>> (interactive)
>> (query-replace-regexp "\(<<\)" "\1cn\,(+ (line-number-at-pos) \#)")
>> )
>>
>> to save typing, but this does not work. What did I wrong?
>
> Lisp string syntax needs additional quoting for regexps, and things like
> \, and \# are not supported outside of interactive use.
>
> I recommend that you first give your command interactively, then use C-x
> Esc Esc to get at the corresponding Lisp verbiage.
>
> --
> David Kastrup
>
^ permalink raw reply [flat|nested] 5+ messages in thread
* Re: replace-regexp in lisp function
2010-01-18 14:06 ` Sven Garbade
@ 2010-01-18 14:11 ` David Kastrup
0 siblings, 0 replies; 5+ messages in thread
From: David Kastrup @ 2010-01-18 14:11 UTC (permalink / raw)
To: Sven Garbade; +Cc: help-gnu-emacs
Sven Garbade <sfgarbade@googlemail.com> writes:
> Hi,
>
> many thanks. C-x Esc Esc gave me:
>
> (query-replace-regexp "\\(<<\\)"
> (quote (replace-eval-replacement concat "\\1cn" (replace-quote (+
> (line-number-at-pos) replace-count)) ",")) nil
> (if (and transient-mark-mode mark-active) (region-beginning))
> (if (and transient-mark-mode mark-active) (region-end)))
>
> which works inside my function. Looks quite complicate for me...
Depending on the application, the expression (if (and
transient-mark-mode mark-active) (region-beginning)) and its cousin can
get replaced by known values, such as (point-min) and (point-max).
--
David Kastrup
^ permalink raw reply [flat|nested] 5+ messages in thread
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2010-01-18 13:01 ` replace-regexp in lisp function David Kastrup
2010-01-18 14:06 ` Sven Garbade
2010-01-18 14:11 ` David Kastrup
2010-01-18 13:11 ` Pascal J. Bourguignon
2010-01-18 9:29 Sven Garbade
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