Re: Is there a function to sort file names by file version number, like "ls -v"?

Re: Is there a function to sort file names by file version number, like "ls -v"?

[Sean McAfee]

florian@fsavigny.de (Florian v. Savigny) writes:
> I am wondering if there is somehow a comparison function (of the same
> category as string-lessp) in Elisp which compares file name strings by
> these version numbers, so I could sort the result of
> directory-file-names in the same way as "ls -v".

I don't think so, but it's easy to write one:

(defun versioned-filename-lessp (a b)
  (labels ((parse (str)
             (string-match "\\(?:~\\([0-9]+\\)~\\)?\\'" str)
             (cons (substring str 0 (match-beginning 0))
                   (and (match-beginning 1)
                        (string-to-number (match-string 1 str))))))
    (save-match-data
      (let ((ap (parse a))
            (bp (parse b)))
        (or (string-lessp (car ap) (car bp))
            (and (not (string-lessp (car bp) (car ap)))
                 (cdr ap)
                 (cdr bp)
                 (< (cdr ap) (cdr bp))))))))

Re: Is there a function to sort file names by file version number, like "ls -v"?

[Florian v. Savigny]

Hi Sean,

thanks so much for being so helpful!

  > I don't think so, but it's easy to write one:

You call that easy ... I'm wondering how long it took you? In any
case, I honestly admire you. (It only ever LOOKS easy when I try, but
it always ends up being complicated.)

  > (defun versioned-filename-lessp (a b)
  >   (labels ((parse (str)

I was wondering about these two functions, "labels" and "parse", but
emacs does not seem to know them either. Are you assuming that some
library is loaded, maybe? (I am using Emacs 24.3.1.)

Best regards, and thanks again,

Florian

Re: Is there a function to sort file names by file version number, like "ls -v"?

[Pascal J. Bourguignon]

florian@fsavigny.de (Florian v. Savigny) writes:

> Hi Sean,
>
> thanks so much for being so helpful!
>
>   > I don't think so, but it's easy to write one:
>
> You call that easy ... I'm wondering how long it took you? In any
> case, I honestly admire you. (It only ever LOOKS easy when I try, but
> it always ends up being complicated.)
>
>   > (defun versioned-filename-lessp (a b)
>   >   (labels ((parse (str)
>
> I was wondering about these two functions, "labels" and "parse", but
> emacs does not seem to know them either. Are you assuming that some
> library is loaded, maybe? (I am using Emacs 24.3.1.)

Sure: (require 'cl) should be the first line of all ~/.emacs files.

-- 
__Pascal Bourguignon__                     http://www.informatimago.com/
A bad day in () is better than a good day in {}.
You can take the lisper out of the lisp job, but you can't take the lisp out
of the lisper (; -- antifuchs

Re: Is there a function to sort file names by file version number, like "ls -v"?

[Sean McAfee]

florian@fsavigny.de (Florian v. Savigny) writes:
> You call that easy ... I'm wondering how long it took you?

Oh, maybe 5-10 minutes, including testing.  I've written similar
routines in other languages before, which sped things up a bit.

>   > (defun versioned-filename-lessp (a b)
>   >   (labels ((parse (str)
>
> I was wondering about these two functions, "labels" and "parse", but
> emacs does not seem to know them either. Are you assuming that some
> library is loaded, maybe? (I am using Emacs 24.3.1.)

labels is a macro that defines local functions, in this case one called
"parse".  See:

http://www.gnu.org/software/emacs/manual/html_node/cl/Obsolete-Macros.html

(Apparently I ought to be using cl-labels instead of labels now.)

It lives in the "cl" (Common Lisp) package, and is loaded when first
used.  You can evaluate the expression (require 'cl) to pull in the
package explicitly.

If it's not clear, the parse routine I defined takes a filename as an
argument, and returns a cons cell that contains the decomposed contents
of the name.  A name with a tilde-delimited version suffix, like say
"foo~5~", is transformed into ("foo" . 5), and a name without such a
suffix, like say "bar", becomes just ("bar" . nil).  The main body of
versioned-filename-lessp just compares two such decompositions.

Re: Is there a function to sort file names by file version number, like "ls -v"?

[Florian v. Savigny]

Hi Sean,

  > If it's not clear, the parse routine I defined takes a filename as
  > an argument, and returns a cons cell that contains the decomposed
  > contents of the name.  A name with a tilde-delimited version
  > suffix, like say "foo~5~", is transformed into ("foo" . 5), and a
  > name without such a suffix, like say "bar", becomes just ("bar"
  > . nil).  The main body of versioned-filename-lessp just compares
  > two such decompositions.

Sorry ... before I read that, I had already had edebug-defun walk me
through the process, which showed me without thinking how it
works. Thanks very much - you actually tought me a /general/ method
for sorting things!

Best regards,

Florian

Is there a function to sort file names by file version number, like "ls -v"?

[Florian v. Savigny]

Hi there,

if you backup files using "cp --backup numbered", cp creates version
numbers like this:

xorg.conf.~1~
xorg.conf.~2~
...
xorg.conf.~9~
xorg.conf.~10~
xorg.conf.~11~
...
xorg.conf.~20~

etc.

As these names are not zero-padded, the normal, alphabetical sorting
will sort them like this:

xorg.conf.~10~
xorg.conf.~11~
...
xorg.conf.~1~
xorg.conf.~20~
xorg.conf.~21~
xorg.conf.~2~
...
xorg.conf.~9~

which is definitely not what is normally useful. For this reason, ls
seems to have the -v switch, which sorts them as shown in the first
listing.

I am wondering if there is somehow a comparison function (of the same
category as string-lessp) in Elisp which compares file name strings by
these version numbers, so I could sort the result of
directory-file-names in the same way as "ls -v".

Is there? (There must be! ;-))

Thank you very much in advance!

Best regards,

Florian