Re: Understanding dotimes skipping by 2

[Marco Wahl <marcowahlsoft@gmail.com>]

Tim Johnson <tim@akwebsoft.com> writes:

> the following code snippet is as follows:
> (setq l `(1 2 3 4 5 6 7 8 9 0))

> ;; iterate through a list two elements at a time
> (let ((x 0))
>   (dotimes (/ (length l) 2)
>     (progn
>       (insert (format "%s %s, " (nth x l) (nth (+ x 1) l)))
>       (setq x (+ x 2)))))
>
> ;; and below are the results
> 1 2, 3 4, 5 6, 7 8, 9 0, nil nil, nil nil, nil nil, nil nil, nil nil, 2
>
> I'm confused about the output (nil etc...)which follow the expected numbers. 
> could someone explain?
> P.S. I get the same output without the `progn form

Looks like "/" is a variable which gets bound to the values of 0 up to
(length l) and the result of the loop is 2.

It's in the documentation (C-h f dotimes).


HTH
-- 
Marco