Re: Problem with position and find (cl)

[Marc Tfardy <m-t-o___CUT__IT@web.de>]

Thierry Volpiatto schrieb:
> Florian Beck <abstraktion@t-online.de> writes:
> 
>> Marc Tfardy <m-t-o___CUT__IT@web.de> writes:
>>
>>> Marc Tfardy schrieb:
>>>> I try with:
>>>> (member '(2) '((1) (2) (3) (4)))
>> `member' tests the components: ›2‹ ist always equal (in the sense of »eq«) to ›2‹
>>
>> Compare:
>>
>> (memq '(2) '((1) (2) (3) (4)))
>> (eq 2 2)
>> (eq '(2) '(2))
>>
>>>> and this gives a expectet results ((2) (3) (4)), but:
>>>> (find '(2) '((1) (2) (3) (4)))
>>>> or
>>>> (position '(2) '((1) (2) (3) (4)))
>>>>
>>>> returns nil. Why?
>> Because  the first and the second »(2)« have the same components but are
>> *different* lists.
>>
>>> But this works:
>>>
>>> (position '(2) '((1) (2) (3) (4)) :test (lambda (x y) (eq (car x) (car
>>> y))))
>>>

> position default test is 'eq, try 'equal

Thanks! It works with equal. But I have another problem.
find (and find-if) returns only first match. Is there another
function that returns all matched elements. Some example:

(find-if-all (lambda (x) (if (eq (nth 2 x) 'byte) t nil)) '((1.1 "x" 
int) (2.2 "y" byte) (3.3 "q" int) (4.4 "b" byte) (5.5 "a" float)))

should returns:
((2.2 "y" byte) (4.4 "b" byte))

I found in cl-*.el nothing like this. Any hints?

regards
Marc