Re: print out all members of a list

["Andreas Röhler" <andreas.roehler@easy-emacs.de>]

Am 01.03.2011 14:10, schrieb Pascal J. Bourguignon:
> Andreas Röhler<andreas.roehler@easy-emacs.de>  writes:
>
>> Am 28.02.2011 16:20, schrieb ken:
>>> (car '("one" "two" "three"))
>>>
>>> prints out "one" ... the first of the list.  How to print out all
>>> elements of the list (in order and with the double quotes around them?
>>> I'm actually looking just to substitute something for "car" and not
>>> write an entire function.  Or is there no such thing?
>>>
>>> Thanks much.
>>>
>>>
>>
>> and still a form delivering with doublequotes...
>>
>> (let ((my-list (list "one" "two" "three")))
>>      (dolist (elem my-list)
>>    (insert (format "\n\"%s\"" elem))))
>
> Why do you write broken code?
>
>      (let ((my-list (list "o\"n\"e" "t\"wo" "th\\\"ree")))
>         (dolist (elem my-list)
>            (insert (format "\n\"%s\"" elem))))
>
>      "o"n"e"
>      "t"wo"
>      "th\"ree"
>
>
> Is it not easier to write code that works?
>
>      (let ((my-list (list "o\"n\"e" "t\"wo" "th\\\"ree")))
>         (dolist (elem my-list)
>            (insert (format "\n%s" (prin1-to-string elem)))))
>
>      "o\"n\"e"
>      "t\"wo"
>      "th\\\"ree"
>
>

Ok, thanks, interesting point.

 From there `concat' read better for me

(let ((my-list (list "o\"n\"e" "t\"wo" "th\\\"ree")))
        (dolist (elem my-list)
           (insert (concat "\n" (prin1-to-string elem)))))

(?) :-)