Re: NON-trivial regular expression problem (could not find on google)

[Yuan Liu <yliu@stemnet.nf.ca.remove_this>]

Peter J. Acklam wrote:
> "Dr. Yuan Liu" <yliu@stemnet.nf.ca.remove_this> wrote:
> 
> 
>>Bournish and Kornish shells all stick with the symbolic
>>path, i.e., foo/bar/.. is always foo.
> 
> 
> Take a look at the following -- it is an example of a case where
> "foo/bar/.." and "foo" is not the same (ksh on Solaris 8):
> 
>     /var/tmp $ mkdir -p foo/fee/fie/foe
>     /var/tmp $ ln -s fee/fie/foe foo/bar
>     /var/tmp $ ls foo
>     bar  fee
>     /var/tmp $ ls foo/bar/..
>     foe

Interesting.  ls and pwd, cd behave differently.  Thanks for pointing out.

Yuan Liu

> In this case, "foo/bar/.." is "foo/fee/fie/foe/.." which is
> "foo/fee/fie" which is *not* the same as "foo".  The reason
> is simply that "foo/bar/.." resolves to a different directory
> than "foo".  So, you can *not* assume "foo/bar/.." is "foo".
> 
> Peter