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From: A Soare <alinsoar@voila.fr>
To: "Emacs   Help  [help-gnu-emacs]" <help-gnu-emacs@gnu.org>
Subject: adress of lisp object is multiple of 8
Date: Tue,  8 May 2007 18:04:10 +0200 (CEST)	[thread overview]
Message-ID: <28221415.79501178640250861.JavaMail.www@wwinf4203> (raw)


Here is the definition of a lisp object.

typedef
union Lisp_Object
  {
    /* Used for comparing two Lisp_Objects;
       also, positive integers can be accessed fast this way.  */
    EMACS_INT i;

    struct
      {
	EMACS_INT val  : VALBITS;
	enum Lisp_Type type : GCTYPEBITS;
      } s;
    struct
      {
	EMACS_UINT val : VALBITS;
	enum Lisp_Type type : GCTYPEBITS;
      } u;
  }
Lisp_Object;

It is memorised on 32 bits. First 3 bits represents the type of object. The others 29 represent a pointer to a structure of that type of object. For example, if adress & 7 is 5, that means that the integer formed of the 29 bits points to a Lisp_Cons.

I do not understand how can I be sure that when the lisp allocs a new space of memory for a given object from enum Lisp_Type, it is allocated to an adress that is multiple of 8 ?

Thanks in advance.

             reply	other threads:[~2007-05-08 16:04 UTC|newest]

Thread overview: 2+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2007-05-08 16:04 A Soare [this message]
2007-05-08 18:57 ` adress of lisp object is multiple of 8 Eli Zaretskii

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