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From: Jeff Clough <jeff@chaosphere.com>
To: help-gnu-emacs@gnu.org
Subject: Re: Emacs Lisp - Reading a sequence of bytes as one integer
Date: Sat, 13 Mar 2010 14:10:22 -0500 (EST)	[thread overview]
Message-ID: <20100313.141022.80614820.jeff@chaosphere.com> (raw)
In-Reply-To: <20100313.131029.39330337.jeff@chaosphere.com>

From: Jeff Clough <jeff@chaosphere.com>
Date: Sat, 13 Mar 2010 13:10:29 -0500 (EST)

> Is there some general way I can tell emacs "Take the three bytes
> following point and make one integer out of them"?

Well, I've managed to figure this out, although it's the "hard way".
I grab the data as a string, then bust out each byte into its own
character/integer and finally I do the math to convert it into an
appropriate value.  My quick and dirty mock-up...

(defun decode-int (a-string)
  (+ (* (string-to-char (substring a-string 0 1)) 256 256)
     (* (string-to-char (substring a-string 1 2)) 256)
     (string-to-char (substring a-string 2 3))))

Still looking for a better way, but I'll put together a nicer version
of the above later that will serve my particular purposes.

Jeff





  reply	other threads:[~2010-03-13 19:10 UTC|newest]

Thread overview: 8+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2010-03-13 16:56 Emacs Lisp - Reading a sequence of bytes as one integer Jeff Clough
2010-03-13 17:15 ` Teemu Likonen
2010-03-13 18:10   ` Jeff Clough
2010-03-13 19:10     ` Jeff Clough [this message]
2010-03-14  8:03       ` Andreas Politz
2010-03-13 19:42     ` Teemu Likonen
2010-03-13 18:49 ` Eli Zaretskii
2010-03-13 19:12   ` Jeff Clough

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