Trouble with regexp

Trouble with regexp

[exits funnel]

Hello,

I have a text file with hundres of lines of the form:

%token FOO_Alter

where 'FOO' is always 'FOO' but 'Alter' is variable. 
I'd like to convert these lines to:

  t_foo_Alter = 'Alter';

using query-replace-regexp but I can't quite get it
right.  Here's what I have so far:

M-x query-replace-regexp RET
%token XTAG_\(a-Z\) RET
  t_xtag_\1 = '\1'; RET

Sadly, I get 0 occurences replaced.  Can anyone set me
straight?  Thanks in advance.

-exits

  


		
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Re: Trouble with regexp

[rgb]

> %token FOO_Alter
>
> where 'FOO' is always 'FOO' but 'Alter' is variable.
> I'd like to convert these lines to:
>
>   t_foo_Alter = 'Alter';

Does this work?

%token FOO_\([a-zA-Z]+\)
t_foo_\1 = '\1';

Re: Trouble with regexp

[Chris McMahan]

I would recommend that you use a macro instead of a regexp, if for no
other reason than I don't know the regexp to use :)


exits funnel <exitsfunnel@yahoo.com> writes:
> Hello,
>
> I have a text file with hundres of lines of the form:
>
> %token FOO_Alter
>
> where 'FOO' is always 'FOO' but 'Alter' is variable. 
> I'd like to convert these lines to:
>
>   t_foo_Alter = 'Alter';
>
> using query-replace-regexp but I can't quite get it
> right.  Here's what I have so far:
>
> M-x query-replace-regexp RET
> %token XTAG_\(a-Z\) RET
>   t_xtag_\1 = '\1'; RET
>
> Sadly, I get 0 occurences replaced.  Can anyone set me
> straight?  Thanks in advance.
>
> -exits

-- 
     (.   .)
  =ooO=(_)=Ooo=====================================
  Chris McMahan | first_initiallastname@one.dot.net
  =================================================

Re: Trouble with regexp

[exits funnel]

> > %token FOO_Alter
> >
> > where 'FOO' is always 'FOO' but 'Alter' is
> variable.
> > I'd like to convert these lines to:
> >
> >   t_foo_Alter = 'Alter';
> 
> Does this work?

Like a charm.  Thanks!

-exits


		
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Re: Trouble with regexp

[Pascal Bourguignon]

"rgb" <rbielaws@i1.net> writes:

>> %token FOO_Alter
>>
>> where 'FOO' is always 'FOO' but 'Alter' is variable.
>> I'd like to convert these lines to:
>>
>>   t_foo_Alter = 'Alter';
>
> Does this work?
>
> %token FOO_\([a-zA-Z]+\)
> t_foo_\1 = '\1';

Given the input file, I'd wouldn't bother matching the exact
characters (you could have digits and underlines) and use:
 
%token FOO_\([^ ]*\)
t_foo_\1 = '\1';

-- 
__Pascal Bourguignon__                     http://www.informatimago.com/
Cats meow out of angst
"Thumbs! If only we had thumbs!
We could break so much!"

Re: Trouble with regexp

[exits funnel]

--- Pascal Bourguignon <spam@mouse-potato.com> wrote:
> Given the input file, I'd wouldn't bother matching
> the exact
> characters (you could have digits and underlines)
> and use:
>  
> %token FOO_\([^ ]*\)
> t_foo_\1 = '\1';

Thanks Pascal, that was even better as I did in fact
run into some '_'s;

-exits


	
		
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Trouble with regexp

[TheLonelyStar]

Hi,

I some trouble with regular expression. I thought, the regexp "\(foo\|bar\)"
should match either foo and bar.
But  if I have a buffer with "foo" in it, the regexp build does not match it
with that :(.

Thanks!
Nathan
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Re: Trouble with regexp

[David Kastrup]

TheLonelyStar <nabble@lonely-star.org> writes:

> Hi,
>
> I some trouble with regular expression. I thought, the regexp "\(foo\|bar\)"
> should match either foo and bar.
> But  if I have a buffer with "foo" in it, the regexp build does not match it
> with that :(.

It does here.  You are probably not doing the right quoting.  Please
remember that the Lisp string syntax requires quoting of quote marks and
backslashes on _top_ of what quoting your regexps will need.

So please post the actual code that fails instead of talking about it.

-- 
David Kastrup, Kriemhildstr. 15, 44793 Bochum

Re: Trouble with regexp

[Alan Mackenzie]

Hi, TLS!

On Thu, 22 May 2008, TheLonelyStar wrote:


> Hi,

> I some trouble with regular expression. I thought, the regexp "\(foo\|bar\)"
> should match either foo and bar.
> But  if I have a buffer with "foo" in it, the regexp build does not match it
> with that :(.

Are you sure your regexp is what you think it is?  If you are typing it 
into an elisp program, you need to write:

     "\\(foo\\|bar\\)"

.  If you've done C-M-s and are typing into the minibuffer, you don't 
double the quotes.

> Thanks!
> Nathan

-- 
Alan Mackenzie (Nuremberg, Germany).

Re: Trouble with regexp

[Joel J. Adamson]

Alan Mackenzie <acm@muc.de> writes:

> Hi, TLS!
>
> On Thu, 22 May 2008, TheLonelyStar wrote:
>
>
>> Hi,
>
>> I some trouble with regular expression. I thought, the regexp "\(foo\|bar\)"
>> should match either foo and bar.
>> But  if I have a buffer with "foo" in it, the regexp build does not match it
>> with that :(.
>
> Are you sure your regexp is what you think it is?  If you are typing
> it into an elisp program, you need to write:
>
>     "\\(foo\\|bar\\)"
>
> .  If you've done C-M-s and are typing into the minibuffer, you don't
> double the quotes.

I think the problem is he's using re-builder, and expecting it to work
the same as regexp Isearch.  If I enter this

"\\(some\\|with\\|regexp\\)"

in re-builder, then I get some matches.  Without the double backslashes
and quoting, it won't match.

But in Regexp Isearch

\(some\|with\|regexp\)

does match.  Confusing, yes, but useful nevertheless.

Joel
-- 
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Biostatistician
Pediatric Psychopharmacology Research Unit
Massachusetts General Hospital
Boston, MA  02114
(617) 643-1432
(303) 880-3109
Public key: http://pgp.mit.edu
http://www.unc.edu/~adamsonj