From: Lute Kamstra <Lute.Kamstra.lists@xs4all.nl>
Cc: emacs-devel@gnu.org
Subject: Re: Adding rassq-delete-all to lisp/subr.el.
Date: Thu, 21 Apr 2005 19:33:21 +0200 [thread overview]
Message-ID: <871x948272.fsf@xs4all.nl> (raw)
In-Reply-To: <854qe267rp.fsf@lola.goethe.zz> (David Kastrup's message of "Tue, 19 Apr 2005 18:39:06 +0200")
David Kastrup <dak@gnu.org> writes:
> Lute Kamstra <Lute.Kamstra.lists@xs4all.nl> writes:
>
>> David Kastrup <dak@gnu.org> writes:
>>
>>> And I am not too fond of quadratic complexity algorithms.
>>
>> Me neither, but I was lazy and adapted assq-delete-all.
>>
>>> If one takes
>>> (defun checkit ()
>>> (setq x nil)
>>> (dotimes (i 100001) (push (cons (- i) i) x))
>>> (float-time
>>> (time-since (prog1 (current-time)
>>> (dotimes (i 101)
>>> (setq x (rassq-delete-all (* 100 i) x)))))))
>>>
>>> The discrepancy seems pretty small after byte compilation, which seems
>>> strange.
>>
>> delq in defined in C and it's only called 101 times.
>
> Ah, right. If we removed all elements piecemeal, this would be
> different.
No, that would still run in linear time. To get quadratic behavior,
you can do this:
(defun checkit ()
(setq x nil)
(dotimes (i 100000)
(push '(a . a) x)
(push '(b . b) x))
(float-time
(time-since
(prog1 (current-time)
(rassq-delete-all 'a x)))))
Lute.
next prev parent reply other threads:[~2005-04-21 17:33 UTC|newest]
Thread overview: 12+ messages / expand[flat|nested] mbox.gz Atom feed top
2005-04-19 13:28 Adding rassq-delete-all to lisp/subr.el Lute Kamstra
2005-04-19 14:06 ` Lute Kamstra
2005-04-19 15:12 ` David Kastrup
2005-04-19 16:23 ` Lute Kamstra
2005-04-19 16:39 ` David Kastrup
2005-04-21 15:30 ` Richard Stallman
2005-04-21 17:33 ` Lute Kamstra [this message]
2005-04-19 22:27 ` Richard Stallman
2005-04-20 9:41 ` Lute Kamstra
2005-04-20 21:42 ` Richard Stallman
2005-04-20 23:23 ` Lute Kamstra
2005-04-21 15:30 ` Richard Stallman
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