From: Glenn Morris <rgm@gnu.org>
To: "Roland Winkler" <winkler@gnu.org>
Cc: 17666@debbugs.gnu.org
Subject: bug#17666: 24.3.91; [regression] call-process in read-only buffers
Date: Mon, 02 Jun 2014 13:37:14 -0400 [thread overview]
Message-ID: <rlioojxlf9.fsf@fencepost.gnu.org> (raw)
In-Reply-To: <42346.74055.958802.21388@gargle.gargle.HOWL> (Roland Winkler's message of "Mon, 2 Jun 2014 11:25:14 -0500")
"Roland Winkler" wrote:
>> > (with-temp-buffer
>> > (let ((buffer-read-only t))
>> > (call-process "true" nil t)))
[...]
> But what is the problem if a process does not have any output?
If you know it isn't going to produce any output, why don't you just
discard the output instead of sending it to a read-only buffer (which is
something that really doesn't make sense)?
(with-temp-buffer
(let ((buffer-read-only t))
(call-process "true" nil nil)))
next prev parent reply other threads:[~2014-06-02 17:37 UTC|newest]
Thread overview: 9+ messages / expand[flat|nested] mbox.gz Atom feed top
2014-06-02 15:01 bug#17666: 24.3.91; [regression] call-process in read-only buffers Roland Winkler
2014-06-02 16:18 ` Stefan Monnier
2014-06-02 16:25 ` Roland Winkler
2014-06-02 17:37 ` Glenn Morris [this message]
2014-06-02 17:45 ` Glenn Morris
2014-06-02 18:34 ` Eli Zaretskii
2014-06-02 18:14 ` Roland Winkler
2014-06-02 17:57 ` Stefan Monnier
2014-06-02 18:42 ` Stefan Monnier
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